前三名产品的 Oracle Quarter SQL 查询答案

【问题标题】：Oracle Quarter SQL Query with top three products前三名产品的 Oracle Quarter SQL 查询
【发布时间】：2016-04-11 19:21:00
【问题描述】：

我正在 Oracle 中从事一个小项目。我需要获得前三名最畅销的产品以及今年以及 4 月至 6 月、7 月至 9 月、10 月至 12 月和 1 月至 3 月四个季度中每个季度的总销量。我已经找到了第一部分，我只需要帮助获得每个产品的 4 个季度总数。希望有人能帮忙，谢谢

这是目前使用的 SQL 命令：

select * from (
  select   "FACTQUANTITY"."PRODUCTID" as "PRODUCTID",
           "DIMPRODUCT"."PRODUCTNAME" as "PRODUCTNAME",
           sum(FACTQUANTITY.QUANTITY) as "QUANTITY" 
  from     "FACTQUANTITY" "FACTQUANTITY",
           "DIMPRODUCT" "DIMPRODUCT" 
  where    "DIMPRODUCT"."PRODUCTID"="FACTQUANTITY"."PRODUCTID" 
  group by FACTQUANTITY.PRODUCTID,
           DIMPRODUCT.PRODUCTNAME
  order by sum(FACTQUANTITY.QUANTITY) desc
)
WHERE ROWNUM <= 3;

【问题讨论】：

标签： oracle

【解决方案1】：

你可以从这里开始：

  select     
     trunc(fact_table.date_column,'Q') as quarter,
    "FACTQUANTITY"."PRODUCTID" ,
    "DIMPRODUCT"."PRODUCTNAME",
     sum(FACTQUANTITY.QUANTITY) as "QUANTITY" 
  from   "FACTQUANTITY" JOIN "DIMPRODUCT" 
       ON "DIMPRODUCT"."PRODUCTID"="FACTQUANTITY"."PRODUCTID" 
  group by 
      FACTQUANTITY.PRODUCTID, DIMPRODUCT.PRODUCTNAME,   trunc(fact_table.date_column,'Q')

    ;

随后，您可以：

with a as (<previous query>)
select * 
from (
  select 
       quarter, 
       productid, 
       productname, 
       quantity,
       row_number() over (partition by quarter order by quantity desc) rnk
  from a
  )
where rnk <= 3;

【讨论】：

【解决方案2】：

SELECT *
FROM   (
  SELECT *,
         ROW_NUMBER() OVER ( PARTITION BY quarter
                             ORDER BY quantity DESC, PRODUCTNAME ASC ) AS rn
  FROM   (
    SELECT   TRUNC( f.datetime, 'Q' ) AS quarter,
             f.PRODUCTID,
             d.PRODUCTNAME,
             sum(f.QUANTITY) AS QUANTITY
    FROM     FACTQUANTITY f
             INNER JOIN
             DIMPRODUCT d
             ON ( d.PRODUCTID = f.PRODUCTID )
    GROUP BY TRUNC( f.datetime, 'Q' ),
             FACTQUANTITY.PRODUCTID,
             DIMPRODUCT.PRODUCTNAME
  )
)
WHERE rn <= 3;

【讨论】：