C 中的平均、最大值和最小值程序

Question

所以我正在用 C 语言编写代码，我需要编写从用户那里获取 n 个数字的代码，并为它们的值找到它们的最小值、最大值、平均值和平方和。到目前为止，我有平均值和平方和部分，但最小值和最大值对我很不利。

请记住，我处于非常初级的水平，还没有达到数组。我只知道逻辑运算符、函数、循环以及 stdlib.h、math.h 和 stdio.h 库的使用。

这是我目前所拥有的。 当我在编译过程中尝试放置 float 和 double 时，average 函数给了我很多问题，所以将它乘以 1.0 来修复它。我什么都有，只有最小和最大。我一直将最后一个条目作为我的最大值，并将 0 作为我的最小值。

#include<stdio.h>
int main()
{
    float average;
    int i, n, count=0, sum=0, squaresum=0, num, min, max;


    printf("Please enter the number of numbers you wish to evaluate\n");
    scanf_s("%d",&n);

    printf("Please enter %d numbers\n",n);

    while(count<n)
    {
        min=0;
        max=0;

            if(num>max)
               max=num;
            if(num<min)
               min=num;

            scanf_s("%d",&num);

        sum = sum+num;
        squaresum = squaresum + (num*num);

        count++;
    }
        average = 1.0*sum/n;

    printf("Your average is %.2f\n",average);
    printf("The sum of your squares is %d\n",squaresum);    



    printf("Your maximum number is %d\n",max);
    printf("Your minimum number is %d\n",min);

return(0);
}

Answer 1

您的代码当前的编写方式，min 必须以较高的值（而不是 0）开始，否则代码将无法工作。选择的最佳值是int 的最大可能值。

您还应该考虑是否要在每次循环中重置这些变量。

Answer 2

你的 while 循环应该是这样的

   min=3;
   max=0;
while(count<n)
    { 

     scanf("%d",&num);
    if(num>max)
    max=num;
    if(num<min)
    min=num;

    sum = sum+num;
    squaresum = squaresum + (num*num);

    count++;
}

我同意Robert Harvey♦.. 你必须设置min

Answer 3

您的算法不太正确。下面是正确的实现：

#include <stdio.h>
#include <stdlib.h>
#include <limits.h>

int main(void)
{
    float average;
    int n, num, count = 0, sum = 0, squaresum = 0;
    int min = INT_MAX, max = INT_MIN;
    bool gotAnswer = false;

    /* Don't Let User Enter Wrong Input */
    while(!gotAnswer)
    {
        printf("Please enter the number of numbers you wish to evaluate: ");
        if(scanf_s("%d", &n) != 1)
        {
            /* User Entered Wrong Input; Clean Up stdin Stream*/
            while(getchar() != '\n')
            {
                 continue;
            }
        }
        else
        {
            /* User Input Was Good */
            gotAnswer = true;
        }
    }

    /* Clear stdin Stream Just In Case */
    while(getchar() != '\n')
        continue;

    while(count < n)
    {
        /* Don't Let User Enter Wrong Input */
        gotAnswer = false;
        printf("Enter number %d: ", count + 1);
        if(scanf_s("%d", &num) != 1)
        {
            /* User Entered Wrong Input; Clean Up stdin Stream */
            while(getchar() != '\n')
                continue;

            /* Let User Try Again */
            continue;
        }
        else
        {
            /* User Input Was Correct */
            gotAnswer = true;

            /* Clear stdin Stream Just In Case */
            while(getchar() != '\n')
                continue;
        }

        if(num > max)
            max = num;
        if(num < min)
            min = num;

        sum += num;
        squaresum += num * num;
        count++;
    }

    average = 1.0 * sum / n;

    printf("Your average is %.2f\n", average);
    printf("The sum of your squares is %d\n", squaresum);    
    printf("Your maximum number is %d\n", max);
    printf("Your minimum number is %d\n", min);

    system("pause");
    return 0;
}

我添加了错误检查和恢复功能。如果您对逻辑有任何疑问，请询问。

Answer 4

您的代码中存在一些问题：

1. num 在哪里读取？你应该在 之前 min 和 max
2. 当while 循环 执行第一次 时，您应该分配 num 到max 和min。

类似的东西：

  int min = 0;
  int max = 0;

  // If your compiler supports C99 standard you can put
  // bool first_time = true;
  int first_time = 1;

  while (count < n) {
    printf("Please, enter the next number\n");
    scanf_s("%d", &num); 

    // If your compiler supports C99 you can put it easier:
    // if (first_time) { 
    if (first_time == 1) {
      first_time = 0;
      max = num;
      min = num;
    }
    else {
      if(num > max)
        max = num;

      if(num < min)
        min = num;
    }
  ...

Answer 5

添加一个布尔值，移动给定值 min，max 0 是循环的开始

#include<stdio.h>
int main()
{
    float average;
    int i, n, count=0, sum=0, squaresum=0, num, min, max;

    bool first = true;
    printf("Please enter the number of numbers you wish to evaluate\n");
    scanf_s("%d",&n);

    printf("Please enter %d numbers\n",n);
        min=0;
        max=0;

    while(count<n)
    {
            scanf_s("%d",&num);

        if (first) {
           first = false;
           min = max = num;
        }
            if(num>max)
               max=num;
            if(num<min)
               min=num;


        sum = sum+num;
        squaresum = squaresum + (num*num);

        count++;
    }
        average = 1.0*sum/n;

    printf("Your average is %.2f\n",average);
    printf("The sum of your squares is %d\n",squaresum);    



    printf("Your maximum number is %d\n",max);
    printf("Your minimum number is %d\n",min);

return(0);
}

还应该考虑检查scanf的返回值

Answer 6

在循环外输入第一个num并将其分配给maxmin

scanf("%d",&num);
max = min = num;  

将你的while循环改为无限循环

while(1) {...} 

现在检查您的计数器count 是否等于n 是否等于break 从无限循环中退出

if(count == n)
    break;  

修改后的完整代码：

#include<stdio.h>
int main()
{
    float average;
    int i, n, count=0, sum=0, squaresum=0, num, min, max;

    printf("Please enter the number of numbers you wish to evaluate\n");
    scanf_s("%d",&n);

   printf("Please enter %d numbers\n",n);

   scanf_s("%d",&num);
   max = min = num;

   while(1)
   {
        if(num>max)
           max=num;
        if(num<min)
           min=num;

     sum = sum+num;
     squaresum = squaresum + (num*num);

     count++;
     if(count == n)
        break;
     scanf_s("%d",&num);

   }
    average = 1.0*sum/n;

printf("Your average is %.2f\n",average);
printf("The sum of your squares is %d\n",squaresum);



printf("Your maximum number is %d\n",max);
printf("Your minimum number is %d\n",min);

return(0);
}

Answer 7

假设您在列表中的第一个数字是最小值和最大值。 将每个下一个字符与当前最小值和当前最大值进行比较并相应更新。

Answer 8

int marks , marks_count=0 , max=0 , min=100 , marks_number=1;
float total , avg;

printf("Hit enter to input marks of 10 student.\n\n");
getchar();

do
{
    printf("Input %d Mark : " , marks_number);
    scanf("%d" ,& marks);


    if (marks>max)
    {
        max=marks;
    }

    else if (marks<min)
    {
        min=marks;
    }

    marks_count++;
    marks_number++;

    total=total+marks;
}

while (marks_count<10);
while (marks_number<10);


avg=total/marks_count;

printf("\n\nAverage marks are : %.2f\n" , avg);
printf("Maximum marks are : %d\n" , max);
printf("Minimum marks are : %d\n\n\n" , min);

Answer 9

您可以使用此代码，它会检查循环是否第一次开始。如果它第一次运行，它将 n 的值分配给最小值和最大值变量，然后继续运行。当它第二次运行时，它会检查并发现程序第二次运行，因此它不会用 n 的值初始化变量而不进行比较。

int n, limit, sum = 0, minimum, maximum;
float average;
bool firstTime = "true";

printf("\nEnter Limit: ");
scanf("%d", &limit);

printf("\nEnter %d numbers: \n", limit);
for (int i = 0; i < limit; i++)
{
    scanf("%d", &n);
    if (firstTime)
    {
        minimum = n;
        maximum = n;
        firstTime = false;
    }
    if (minimum > n)
    {
        minimum = n;
    }

    if (maximum < n)
    {
        maximum = n;
    }
    sum = sum + n;
}

average = sum / limit;
printf("\nMinimum: %d", minimum);
printf("\nMaximum: %d", maximum);
printf("\nSum: %d", sum);
printf("\nAverage: %.3lf", average);