上传音频文件时使用 HttpURLConnection 传递参数

Question

当我从堆栈溢出答案之一中获取代码时。 Send .txt file, document file to the server in android

修改以下代码，我正在尝试将音频/视频文件发布到在线 php 服务器。一切正常，文件正在正确上传并保存在数据库中，但问题是我也在发送文件参数，以便我可以识别哪个用户正在发送录音，（user_id 和 Candidate_id 和file_type) 但在数据库中它们的值为 null/0。

请有人告诉我我的代码有什么问题，为什么它不适用于参数。当我使用 POSTMAN 检查我的 php 端服务器时，所有值都正确保存在文件中。

try {
            FileInputStream fileInputStream = new FileInputStream(
                    sourceFile);
            URL url = new URL(Config.URL_UPLOAD);
            conn = (HttpURLConnection) url.openConnection();
            conn.setDoInput(true); // Allow Inputs
            conn.setDoOutput(true); // Allow Outputs
            conn.setUseCaches(false); // Don't use a Cached Copy
            conn.setRequestMethod("POST");
            conn.setRequestProperty("Connection", "Keep-Alive");
            conn.setRequestProperty("ENCTYPE", "multipart/form-data");
            conn.setRequestProperty("Content-Type",
                    "multipart/form-data;boundary=" + boundary);
            conn.setRequestProperty("uploadedfile", fileName);

            dos = new DataOutputStream(conn.getOutputStream());
            //here am adding the params

            param.put("user_id", Constants.user_id);
            param.put("candidate_id", "candiidateid1");
            param.put("file_type", Constants.file_type);
            BufferedWriter writer = new BufferedWriter(
                    new OutputStreamWriter(dos, "UTF-8"));
            writer.write(getPostDataString(param));
            dos.writeBytes(twoHyphens + boundary + lineEnd);
            dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + fileName + "\"" + lineEnd);

            dos.writeBytes(lineEnd);

            // create a buffer of maximum size
            bytesAvailable = fileInputStream.available();

            bufferSize = Math.min(bytesAvailable, maxBufferSize);
            buffer = new byte[bufferSize];

            // read file and write it into form...
            bytesRead = fileInputStream.read(buffer, 0, bufferSize);

            while (bytesRead > 0) {

                dos.write(buffer, 0, bufferSize);
                bytesAvailable = fileInputStream.available();
                bufferSize = Math.min(bytesAvailable, maxBufferSize);
                bytesRead = fileInputStream.read(buffer, 0, bufferSize);

            }

            // send multipart form data necesssary after file data...
            dos.writeBytes(lineEnd);
            dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

            dialog.dismiss();
            // Responses from the server (code and message)
            serverResponseCode = conn.getResponseCode();
            String serverResponseMessage = conn.getResponseMessage();

            Log.i("uploadFile", "HTTP Response is : "
                    + serverResponseMessage + ": " + serverResponseCode);
            DataInputStream inStream = null;
            if (serverResponseCode == 200) {
                try {
                    Log.e("isStream = ", "" + inStream);
                    inStream = new DataInputStream(conn.getInputStream());
                    String str;
                    Log.e("isStream = ", "" + inStream);
                    while ((str = inStream.readLine()) != null) {
                        Log.e("Debug", "Server Response " + str);
                    }
                    inStream.close();
                    Log.e("isStream = ", "" + inStream);
                } catch (IOException ioex) {
                    Log.e("Debug", "error: " + ioex.getMessage(), ioex);
                }

            }

            // close the streams //
            fileInputStream.close();
            dos.flush();
            dos.close();

        } catch (MalformedURLException ex) {

            dialog.dismiss();
            ex.printStackTrace();


            Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
        } catch (Exception e) {

            dialog.dismiss();
            e.printStackTrace();


            Log.e("Upload file to server ",
                    "Exception : " + e.getMessage(), e);
        }

Answer 1

参考下面的网址，它有明确的答案来传递参数

Sending files using POST with HttpURLConnection