如何根据布尔属性对对象数组进行排序？

Question

我在表格中列出了用户列表。 活跃用户应该排在非活跃用户之上。

我正在尝试使用 lodash sortBy 函数制作这个 sort，但没有成功。

userArray 的外观如下：

const userArray [
  { 
    // I need to show users which have disabled = false first 
    // and then users with disabled = true
    disabled: true,  // <==========
    email: "hgaither@cmregent.com",
    firstName: "Harriet",
    lastName: "Gaither",
    role: "claimsHandlerSupervisor",
    userId: "03VFpxtMWgY1jKDHDLcrWSw1qzx1",
  }, 
  {
   disabled: false,  // <===========
   email: "hgaither@cmregent.com",
   firstName: "Harriet",
   lastName: "Gaither",
   role: "claimsHandlerSupervisor",
   userId: "03VFpxtMWgY1jKDHDLcrWSw1qzx1",
 }, 
]

这里是带有用户数组和 sortBy loadsh 函数的代码笔： https://codepen.io/nikolatrajkovicq/pen/pGXdpM?editors=1112

欢迎任何建议。

Answer 1

你可以像这样使用sort：

const userArray=[{disabled:true,email:"hgaither@cmregent.com",firstName:"Harriet",lastName:"Gaither",role:"claimsHandlerSupervisor",userId:"03VFpxtMWgY1jKDHDLcrWSw1qzx1",},{disabled:false,email:"hgaither@cmregent.com",firstName:"Harriet",lastName:"Gaither",role:"claimsHandlerSupervisor",userId:"03VFpxtMWgY1jKDHDLcrWSw1qzx1",},]

userArray.sort((a,b) => a.disabled - b.disabled)
console.log(userArray)

您可以只减去compareFunction 中的布尔属性。这是因为强制

true - false === 1
false - true === -1
true - true === 0

Answer 2

您可以使用sort

const userArray = [{disabled:true,email:"hgaither@cmregent.com",firstName:"Harriet",lastName:"Gaither",role:"claimsHandlerSupervisor",userId:"03VFpxtMWgY1jKDHDLcrWSw1qzx1",},{disabled:false,email:"hgaither@cmregent.com",firstName:"Harriet",lastName:"Gaither",role:"claimsHandlerSupervisor",userId:"03VFpxtMWgY1jKDHDLcrWSw1qzx1",},{disabled:true,email:"hgither@cmregent.com",firstName:"Hrriet",lastName:"Gither",role:"claisHandlerSupervisor",userId:"0VFpxtMWgY1jKDHDLcrWSw1qzx1",},]

let op = userArray.sort(({disabled:A}, {disabled:B})=> A-B)

console.log(op)