无法使用 XAMPP for mac 添加到 mySQL 数据库

Question

您好，我目前正在尝试将数据添加到我的用户登录数据库，但是由于某种原因，当我注册新用户时，我的数据库没有更新。

这是我来自 user.inc.php 的代码：

<?php
//checks if username already exists in database
function user_exists($user)
{
    $user = mysqli_real_escape_string($user);
    $total = mysqli_query("SELECT user_id FROM user_system WHERE user_name= ('$user')");

    return (mysql_result($total, 0) == '1') ? true : false;
}

//checks if username and password combo is valid
function valid_credent($user, $pass)
{
    $user = mysqli_real_escape_string($user);
    $pass = sha1($pass);
    $total = mysqli_query("SELECT COUNT user_id FROM users 
                        WHERE user_name = '$user' AND 
                        user_password = '$pass' ");

    return(mysql_result($total, 0) == '1') ? true : false;
}

//add user to database
function add_user($user, $pass)
{
    $user = mysqli_real_escape_string(htmlentities($user));
    $pass = sha1($pass);

    $queryStr = "INSERT INTO users (user_name, user_password) VALUES ('$user', '$pass')";
    $R = mysqli_query($mysqli,$queryStr);
}
?>

当我尝试添加视图错误时，我的注册页面上也有警告

Warning: mysql_result() expects parameter 1 to be resource, boolean given in /Applications/XAMPP/xamppfiles/htdocs/PostalCloud/core/user.inc.php on line 8

第 8 行：

return (mysql_result($total, 0) == '1') ? true : false;

我尝试过使用“sanitize()”，但它不存在。

更新：修改代码后仍然出现错误。这是我的 register.php 代码的一部分，我有一个使用 mysqli 连接到数据库的 init.inc.php。

<?php
include('init.inc.php');

$errors = array();

if(isset($_POST['username'], $_POST['password'], $_POST['repeatPassword']))
{
    if(empty($_POST['username']))
    {
        $errors[] = 'The username cannot by empty. ';
    }

    if(empty($_POST['password']) || empty($_POST['repeatPassword']))
    {
        $errors[] = 'The password cannot by empty. ';
    }

    if($_POST['password'] !== $_POST['repeatPassword'])
    {
        $errors[] = 'Password verification failed. ';
    }

    if(user_exists($_POST['username']))
    {
        $errors[] = 'The username you entered is already taken. ';
    }

    if(empty($errors))
    {
        add_user($_POST['username'], $_POST['password']);

        $_SESSION['username'] = htmlentities($_POST['username']);

        header('Location: protected.php');
        die();
    }
}
?>

init.inc.php：

<?php
session_start();

$exceptions = array('register', 'login');

$page = substr(end(explode('/',$_SERVER['SCRIPT_NAME'])), 0, -4);

if(in_array($page, $exceptions) === false)
{
    if(isset($_SESSION['username']) === false)
    {
        header('Location: login.php');
        die();
    }
}

$mysqli = mysqli_connect('localhost','root','', 'user_system');

$path = dirname(__FILE__);

include("{$path}/core/user.inc.php");
?>

Answer 1

问题在于 mysql_query() 返回的是布尔值而不是结果资源。发生这种情况的原因有两个：

1. 您执行了返回成功/失败而不是结果的查询 设置（例如更新）

2. 您的查询失败

您的查询包含列名的单引号。应该删除：

$total = mysqli_query("SELECT user_id FROM user_system WHERE user_name= '$user'");