如何使用 pyOpenssl 解码 CSR [关闭]答案

【问题标题】：How to decode CSR using pyOpenssl [closed]如何使用 pyOpenssl 解码 CSR [关闭]
【发布时间】：2015-07-30 16:51:40
【问题描述】：

从网页中获取字符串

-----BEGIN NEW CERTIFICATE REQUEST-----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-----END NEW CERTIFICATE REQUEST-----

如何将其解码为纯文本，如

Certificate information
Common name: www.xxx.net
Organization:xxx.net
Organizational unit:xxx.net
City/locality:bj
State/province:bj
Country:CN
Signature algorithm:SHA1
Key algorithm:RSA
Key size:1024

我知道有第三方 pyopenssl，但不确定如何处理来自 Web 前端的字符串缓冲区。或者你有什么更好的主意吗？谢谢

【问题讨论】：

标签： python decoder csr pyopenssl

【解决方案1】：

您可以使用OpenSSL.crypto.load_certificate_request() 加载证书，然后从那里访问密钥和主题详细信息，例如

import OpenSSL.crypto
from OpenSSL.crypto import load_certificate_request, FILETYPE_PEM

csr = '''-----BEGIN NEW CERTIFICATE REQUEST-----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-----END NEW CERTIFICATE REQUEST-----'''

req = load_certificate_request(FILETYPE_PEM, csr)
key = req.get_pubkey()
key_type = 'RSA' if key.type() == OpenSSL.crypto.TYPE_RSA else 'DSA'
subject = req.get_subject()
components = dict(subject.get_components())
print "Common name:", components['CN']
print "Organisation:", components['O']
print "Orgainistional unit", components['OU']
print "City/locality:", components['L']
print "State/province:", components['ST']
print "Country:", components['C']
print "Signature algorithm:", '?'
print "Key algorithm:", key_type
print "Key size:", key.bits()

很遗憾我不知道如何获取签名算法。

【讨论】：

是的，这对我有用。谢谢，虽然这里的密钥大小似乎不正确。
@kent：很好。我认为密钥大小是正确的，它与openssl req -text <csr.pem 报告的相同，输出Public-Key: (1024 bit)
是的，使用 openssl req 命令密钥大小为 1024 位，而通过 pyopenssl 运行 key.bit，公钥 2048 位。
@kent：这很奇怪。 key.bits() 在你的问题中给我 1024 的 CSR。
另见openssl req -text 和openssl.org/docs/manmaster/man1/openssl-req.html 上的文档，其中还包括签名算法。