如何在应用程序中为所需页面实现 HTTPS？

Question

我们正在尝试为应用程序中的某些页面实现 HTTPS。因此，我们更改了 tomcat server.xml 以进行 HTTPS 调用，如下所示：

<Connector
           port="8080"
           protocol="HTTP/1.1"
           connectionTimeout="20000"
           redirectPort="8443"
           acceptCount="100"
           maxKeepAliveRequests="15"
           SSLEnabled="true"
           scheme="https"
           secure="true"
     clientAuth="false" sslProtocol="TLS"
     keystoreFile="/webapps/test.bin"
           keystorePass="test"/>

在应用程序 web.xml 中：

<security-constraint>
<web-resource-collection>
<web-resource-name>securedapp</web-resource-name>
<url-pattern>/*</url-pattern>
</web-resource-collection>
<user-data-constraint>
<transport-guarantee>CONFIDENTIAL</transport-guarantee>
</user-data-constraint>
</security-constraint>

所以，HTTPS 正在申请所有页面。如何限制所需页面的 HTTPS。

我们将不胜感激。

Answer 1

Spring Security Interceptor 有一个参数requires-channel。将此参数设置为 https 以对匹配拦截器的 url 模式强制执行它。

<beans xmlns="http://www.springframework.org/schema/beans" xmlns:security="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:util="http://www.springframework.org/schema/util" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
            http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.4.xsd
            http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd">

   <security:http>
       <security:intercept-url pattern="/login" access="permitAll"
           requires-channel="https"/>
   </security:http> 

</bean>

Answer 2

创建下面的类

public class RestHttpRequestFilter implements Filter {

   public void destroy() {

   }

   public void doFilter(ServletRequest servletRequest,
                ServletResponse servletResponse, FilterChain filterChain)
                throws IOException, ServletException {
     // if the ServletRequest is an instance of HttpServletRequest
     if (servletRequest instanceof HttpServletRequest) {
        HttpServletRequest httpServletRequest = (HttpServletRequest) servletRequest;
            System.out.println(httpServletRequest.getRequestURL());
            if (httpServletRequest.getRequestURL().toString().contains("/user/account")
                        && servletRequest.getProtocol().contains("HTTP")) {
                    throw new ResourceNotFoundException(
                            "The url should be HTTPS");
           }
       filterChain.doFilter(httpServletRequest, servletResponse);
     } else {
           // otherwise, continue on in the chain with the ServletRequest and
           // ServletResponse objects
           filterChain.doFilter(servletRequest, servletResponse);
     }  
     return;
   }

   public void init(FilterConfig filterConfig) throws ServletException {}

}

web.xml 条目

    <filter>
        <filter-name>simpleFilter</filter-name>
        <filter-class>RestHttpRequestFilter</filter-class>
    </filter>

    <filter-mapping>
        <filter-name>simpleFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

Answer 3

简单的解决方案是使用 HttpFilter 来检查协议和 URL 模式，并决定是将调用转发给应用程序还是抛出会导致用户看到错误页面的异常。