【发布时间】:2018-08-17 08:52:59
【问题描述】:
我需要在我的 Android 应用中扫描 wifi 接入点列表。我过去使用 java 做过,但我的 kotlin 代码无法正常工作。
我的代码:
var resultList = ArrayList<ScanResult>()
lateinit var wifiManager: WifiManager
val broadcastReceiver = object : BroadcastReceiver() {
override fun onReceive(contxt: Context?, intent: Intent?) {
resultList = wifiManager.scanResults as ArrayList<ScanResult>
Log.d("TESTING", "onReceive Called")
}
}
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
wifiManager = this.applicationContext.getSystemService(Context.WIFI_SERVICE) as WifiManager
}
override fun onGridTileClicked(x: Int, y: Int) {
startScanning()
}
fun startScanning() {
registerReceiver(broadcastReceiver, IntentFilter(WifiManager.SCAN_RESULTS_AVAILABLE_ACTION))
Handler().postDelayed({
stopScanning()
}, 10000)
}
fun stopScanning() {
unregisterReceiver(broadcastReceiver)
val axisList = ArrayList<Axis>()
for (result in resultList) {
axisList.add(Axis(result.BSSID, result.level))
}
Log.d("TESTING", axisList.toString())
}
永远不会调用 onReceive() 函数,并且我在清单中声明了 ACCESS_FINE_LOCATION 和 ACCESS_WIFI_STATE ,所以我不确定我做错了什么。我确定我遗漏了一些明显的东西,但我们将不胜感激。谢谢!
【问题讨论】:
-
也许,在
startScanning方法中注册接收器后,您错过了wifiManager.startScan()调用 -
@StefanGolubović 我知道这很明显!再次感谢,我的朋友。
标签: android kotlin android-wifi