接受的答案有缺陷;缺陷如下所示。这是一个解决方案的演示,带有一个测试批次:
TestScheduler ts = new TestScheduler();
var source = ts.CreateHotObservable<char>(
new Recorded<Notification<char>>(200.MsTicks(), Notification.CreateOnNext('A')),
new Recorded<Notification<char>>(300.MsTicks(), Notification.CreateOnNext('B')),
new Recorded<Notification<char>>(400.MsTicks(), Notification.CreateOnNext('A')),
new Recorded<Notification<char>>(500.MsTicks(), Notification.CreateOnNext('A')),
new Recorded<Notification<char>>(510.MsTicks(), Notification.CreateOnNext('C')),
new Recorded<Notification<char>>(550.MsTicks(), Notification.CreateOnNext('B')),
new Recorded<Notification<char>>(610.MsTicks(), Notification.CreateOnNext('B'))
);
var target = source.TimedDistinct(TimeSpan.FromMilliseconds(300), ts);
var expectedResults = ts.CreateHotObservable<char>(
new Recorded<Notification<char>>(200.MsTicks(), Notification.CreateOnNext('A')),
new Recorded<Notification<char>>(300.MsTicks(), Notification.CreateOnNext('B')),
new Recorded<Notification<char>>(500.MsTicks(), Notification.CreateOnNext('A')),
new Recorded<Notification<char>>(510.MsTicks(), Notification.CreateOnNext('C')),
new Recorded<Notification<char>>(610.MsTicks(), Notification.CreateOnNext('B'))
);
var observer = ts.CreateObserver<char>();
target.Subscribe(observer);
ts.Start();
ReactiveAssert.AreElementsEqual(expectedResults.Messages, observer.Messages);
解决方案包括TimedDistinct 的许多重载,允许IScheduler 注入以及IEqualityComparer<T> 注入,类似于Distinct。忽略所有这些重载,解决方案依赖于辅助方法StateWhere,它有点像Scan 和Where 的组合:它像Where 一样过滤,但允许您像@ 一样在其中嵌入状态987654331@。
public static class RxState
{
public static IObservable<TSource> TimedDistinct<TSource>(this IObservable<TSource> source, TimeSpan expirationTime)
{
return TimedDistinct(source, expirationTime, Scheduler.Default);
}
public static IObservable<TSource> TimedDistinct<TSource>(this IObservable<TSource> source, TimeSpan expirationTime, IScheduler scheduler)
{
return TimedDistinct<TSource>(source, expirationTime, EqualityComparer<TSource>.Default, scheduler);
}
public static IObservable<TSource> TimedDistinct<TSource>(this IObservable<TSource> source, TimeSpan expirationTime, IEqualityComparer<TSource> comparer)
{
return TimedDistinct(source, expirationTime, comparer, Scheduler.Default);
}
public static IObservable<TSource> TimedDistinct<TSource>(this IObservable<TSource> source, TimeSpan expirationTime, IEqualityComparer<TSource> comparer, IScheduler scheduler)
{
var toReturn = source
.Timestamp(scheduler)
.StateWhere(
new Dictionary<TSource, DateTimeOffset>(comparer),
(state, item) => item.Value,
(state, item) => state
.Where(kvp => item.Timestamp - kvp.Value < expirationTime)
.Concat(
!state.ContainsKey(item.Value) || item.Timestamp - state[item.Value] >= expirationTime
? Enumerable.Repeat(new KeyValuePair<TSource, DateTimeOffset>(item.Value, item.Timestamp), 1)
: Enumerable.Empty<KeyValuePair<TSource, DateTimeOffset>>()
)
.ToDictionary(kvp => kvp.Key, kvp => kvp.Value, comparer),
(state, item) => !state.ContainsKey(item.Value) || item.Timestamp - state[item.Value] >= expirationTime
);
return toReturn;
}
public static IObservable<TResult> StateSelectMany<TSource, TState, TResult>(
this IObservable<TSource> source,
TState initialState,
Func<TState, TSource, IObservable<TResult>> resultSelector,
Func<TState, TSource, TState> stateSelector
)
{
return source
.Scan(Tuple.Create(initialState, Observable.Empty<TResult>()), (state, item) => Tuple.Create(stateSelector(state.Item1, item), resultSelector(state.Item1, item)))
.SelectMany(t => t.Item2);
}
public static IObservable<TResult> StateWhere<TSource, TState, TResult>(
this IObservable<TSource> source,
TState initialState,
Func<TState, TSource, TResult> resultSelector,
Func<TState, TSource, TState> stateSelector,
Func<TState, TSource, bool> filter
)
{
return source
.StateSelectMany(initialState, (state, item) =>
filter(state, item) ? Observable.Return(resultSelector(state, item)) : Observable.Empty<TResult>(),
stateSelector);
}
}
接受的答案有两个缺陷:
- 不接受
IScheduler 注入,这意味着很难在Rx 测试框架内进行测试。这很容易解决。
- 它依赖于可变状态,这在 Rx 等多线程框架中效果不佳。
问题 #2 在多个订阅者中很明显:
var observable = Observable.Range(0, 5)
.DistinctFor(TimeSpan.MaxValue)
;
observable.Subscribe(i => Console.WriteLine(i));
observable.Subscribe(i => Console.WriteLine(i));
遵循常规 Rx 行为的输出应该输出 0-4 两次。相反,0-4 只输出一次。
这是另一个示例缺陷:
var subject = new Subject<int>();
var observable = subject
.DistinctFor(TimeSpan.MaxValue);
observable.Subscribe(i => Console.WriteLine(i));
observable.Subscribe(i => Console.WriteLine(i));
subject.OnNext(1);
subject.OnNext(2);
subject.OnNext(3);
这会输出一次1 2 3,而不是两次。
这是MsTicks的代码:
public static class RxTestingHelpers
{
public static long MsTicks(this int ms)
{
return TimeSpan.FromMilliseconds(ms).Ticks;
}
}