【发布时间】:2018-06-03 12:46:04
【问题描述】:
我有一个名为 searchResult() 的动作创建者,它从 Firebase 获取数据,然后根据另一个名为 SearchReducer 的缩减程序(由动作创建者 searchChanged() 创建)中的一个名为“搜索”的状态对其进行过滤。代码如下所示:
export const searchResult = () => {
const { currentUser } = firebase.auth();
return (dispatch, getState) => {
firebase.database().ref(`/users/${currentUser.uid}/entries`)
.orderByChild('uid')
.on('value', snapshot => {
const myObj = snapshot.val();
const { search } = getState().searching;
const list = _.pickBy(myObj, (((value) =>
value.make.indexOf(search) !== -1 ||
value.model.indexOf(search) !== -1) && ((value) =>
value.sold === false)));
dispatch({ type: SEARCH_RESULT_SUCCESS, payload: list });
});
};
};
代码运行,但没有过滤任何内容。使用 redux 调试器,我可以看到“搜索”发生了变化。我的语法有问题吗?任何帮助,将不胜感激。这是我的其他代码:
Action Creator searchChanged():
export const searchChanged = (text) => {
return {
type: SEARCH_CHANGED,
payload: text
};
};
Reducer SearchReducer:
import {
SEARCH_CHANGED,
} from '../actions/types';
const INITIAL_STATE = {
search: '',
};
export default (state = INITIAL_STATE, action) => {
switch (action.type) {
case SEARCH_CHANGED:
return { ...state, search: action.payload };
default:
return state;
}
};
searchResult() 的 Reducer 称为 EntryReducer:
import {
SEARCH_RESULT_SUCCESS,
ENTRY_FETCH_SUCCESS,
SOLD_RESULT_SUCCESS
} from '../actions/types';
const INITIAL_STATE = [];
export default (state = INITIAL_STATE, action) => {
switch (action.type) {
case ENTRY_FETCH_SUCCESS:
return action.payload;
case SEARCH_RESULT_SUCCESS:
return action.payload;
case SOLD_RESULT_SUCCESS:
return action.payload;
default:
return state;
}
};
这里是 combineReducers() 函数:
import { combineReducers } from 'redux';
import AuthReducer from './AuthReducer';
import EntryFormReducer from './EntryFormReducer';
import EntryReducer from './EntryReducer';
import SearchReducer from './SearchReducer';
import PasswordReducer from './PasswordReducer';
export default combineReducers({
auth: AuthReducer,
entryForm: EntryFormReducer,
employees: EntryReducer,
searching: SearchReducer,
pw: PasswordReducer
});
这里是 searchChanged() 被调用的地方,然后是 searchResult():
class Search extends Component {
//onSearchChange() is just the onChangeText binding for the text input.
onSearchChange(text) {
this.props.searchChanged(text);
searchResult();
}
========================== 新编辑部分=================== =============
现在我在我的搜索组件中使用 mapDispatchToProps。但是,我仍然会遇到错误,或者在我输入搜索输入时什么也没有发生。整个组件看起来像这样(它返回一个错误,即 searchResult 不是一个函数。我从https://learn.co/lessons/map-dispatch-to-props-readme 得到我的方向):
import React, { Component } from 'react';
import { View } from 'react-native';
import { connect } from 'react-redux';
import { bindActionCreators } from 'redux';
import { Icon } from 'react-native-vector-icons';
import { searchChanged, searchResult } from '../actions';
import Card from './common/Card';
import CardSection from './common/CardSection';
import Input from './common/Input';
class Search extends Component {
onSearchChange(text) {
this.props.searchChanged(text);
this.store.props.dispatch(searchResult());
}
render() {
return (
<View>
<Input
placeholder="Search"
onChangeText={this.onSearchChange.bind(this)}
value={this.props.search}
returnKeyType={'search'}
/>
</View>
);
}
}
const mapStateToProps = state => {
return {
search: state.searching.search
};
};
const mapDispatchToProps = (dispatch) => {
return bindActionCreators({
searchResult: searchResult
}, dispatch);
};
export default connect(mapStateToProps, { searchChanged }, mapDispatchToProps)(Search);
仅使用:
onSearchChange(text) {
this.props.searchChanged(text);
dispatch(searchResult());
}
返回一个错误,即 dispatch 是一个未声明的变量。如何正确格式化此组件,以便它正确理解 mapDispatchToState?
【问题讨论】:
-
您是否尝试将您在班级中的操作从 searchResult() 修改为 this.props.searchResult()?
-
您必须致电
dispatch(searchResult()) -
@DennisFrea 是的,我也试过了......结果相同。感谢您的建议!
-
@Eric Guan 我在哪里调用 dispatch (searchResult())?我试图在 searchChanged() 中调用它,但我可能语法错误。具体会是什么样子?谢谢!
-
您在
searchResult()内调用onSearchChange的确切位置。不要调用searchResult(),而是调用dispatch(searchResult())你需要导入redux store 才能访问dispatch 函数。或者,如果您使用 react-redux,请使用 mapDispatchToProps。
标签: reactjs react-native redux redux-thunk