【问题标题】:[MySQL][PHP] Have not the same result with sub query : php call VS phpMyAdmin[MySQL][PHP] 子查询结果不一样:php call VS phpMyAdmin
【发布时间】:2017-07-07 13:40:46
【问题描述】:

我试图找出问题所在,但我转身却找不到有同样问题的人...

所以我有这个要求:

select killer as idPlayer FROM
(SELECT v.idPlayer as victim, v.name as vicName,k.idPlayer as killer, k.name as kilName, count(*) as number
FROM stats_players v
LEFT OUTER JOIN stats_events e ON v.idPlayer = e.idPlayerVictim
LEFT OUTER JOIN stats_players k ON e.idPlayer = k.idPlayer
WHERE e.type="PVP"  
GROUP BY v.idPlayer,k.idPlayer
HAVING COUNT(*) > 3 ORDER BY COUNT(*) DESC) AS T
group by killer
order by count(*) DESC, sum(number) DESC
LIMIT 1

在 PhPMyAdmin 中运行良好,它返回 1 条记录,正是我想要的。

当我以完全相同的请求使用 Php Call(带有 PDO)时:

try {
    $bdd = new PDO('mysql:host=' . SQL_HOST . ';dbname=' . SQL_DBASE, SQL_USER, SQL_PASS);
    $bdd->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

    $bdd->query('SET session wait_timeout=120');
    $bdd->query('SET session interactive_timeout=120');

} catch (PDOException $e) {
    die('Error during the connection to the  MYSQL database : ' . $e->getMessage());
}

$title['request'] = 'select killer as idPlayer FROM
    (SELECT v.idPlayer as victim, v.name as vicName,k.idPlayer as killer, k.name as kilName, count(*) as number
    FROM stats_players v
    LEFT OUTER JOIN stats_events e ON v.idPlayer = e.idPlayerVictim
    LEFT OUTER JOIN stats_players k ON e.idPlayer = k.idPlayer
    WHERE e.type="PVP"  
    GROUP BY v.idPlayer,k.idPlayer
    HAVING COUNT(*) > 3 ORDER BY COUNT(*) DESC) AS T
    group by killer
    order by count(*) DESC, sum(number) DESC
    LIMIT 1';

$playerList = request_db($bdd,$title['request']);

function request_db($bdd, $request, $txt = '') {
    try {
        if (isset($_GET['debug']) && $_GET['debug'] == 'request') {
            echo $request . '<br>';
            // logfile('requete : ' . $request);
        }

        $timeReqStart = microtime(true);
        $result = $bdd->query($request);
        $timeReqEnd = microtime(true);
        $timeReq = $timeReqEnd - $timeReqStart;
        if ($txt != '') {
            echo $txt . '<br>';
        }
        if (preg_match("/^SELECT/", $request)) { /* Return the ID of the last request (INSERT ONLY) */
            $res_tab = $result->fetchAll();
            $result->closeCursor();
            return $res_tab;
        } else if (preg_match("/^INSERT/", $request) || preg_match("/^UPDATE/", $request)) { /* All that not insert return table */
            echo 'Time Process request : ' . number_format($timeReq, 3) . ' sec <br>';
            return $bdd->lastInsertId();
        }
    } catch (Exception $e) {
        echo 'Error while contacting the database. Please contact the administrator. <br>';
        logfile($request);
        logfile('request error :' . $e->getMessage());
        if (isset($_GET['debug'])) {
            echo 'request : ' . $request . '<br>';
            die('Error during the request to the MYSQL database : <br>' . $e->getMessage());
        }
    }
}

结果什么也没给我。

所以我尝试像这样删除请求中的子查询:

SELECT v.idPlayer as victim, v.name as vicName,k.idPlayer as killer, k.name as kilName, count(*) as number
    FROM stats_players v
    LEFT OUTER JOIN stats_events e ON v.idPlayer = e.idPlayerVictim
    LEFT OUTER JOIN stats_players k ON e.idPlayer = k.idPlayer
    WHERE e.type="PVP"  
    GROUP BY v.idPlayer,k.idPlayer
    HAVING COUNT(*) > 3 ORDER BY COUNT(*) DESC

这两种操作(phpMyAdmin 或通过 PhpCAll)都可以正常工作,我在这两种情况下都有很好的结果。

为什么 php 调用不需要子查询,而它在 phpmyadmin 上运行良好? :( (我正在使用 WAMP 服务器)

谢谢,

【问题讨论】:

  • 你能把你的php代码也贴出来吗?
  • 刚刚在我的 pdo 调用之后添加了下一行代码!
  • 我们不知道$request 长什么样。
  • 好的,我现在已经把我所有的代码都放好了 :) 应该会更好
  • 下一个问题是什么是 $bdd 以及它在哪里定义,...

标签: php mysql phpmyadmin


【解决方案1】:

好的,问题来自我的请求开始时的“选择”,在我的函数“request_db()”中,我的条件等待一个“/^SELECT/”,然后我向它发送一个“选择”。它区分大小写,所以在减号时它不起作用:)

我将我的请求从“选择”更改为“选择”,现在它就像一个魅力。

【讨论】:

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