【发布时间】:2019-09-24 06:01:06
【问题描述】:
我正在尝试一次插入父对象 (BulkSmsDataset) 及其子对象 (BulkSmsRecipient)。我使用 Hibernate 5 和 MariaDB 10.1。我应该能够创建一个 BulkSmsDataset 并用新对象填充List<BulkSmsRecipientEntity> bulkSmsRecipientEntityList 然后一次持久化整个事情对吗?但是当我尝试这样做时,Hibernate 没有在 BulkSmsDatasetEntity 对象上正确设置 FK dataset_id。
我得到以下异常:
Hibernate: insert into bulk_sms_dataset (job_id, name, template) values (?, ?, ?)
Hibernate: insert into bulk_sms_recipient (dataset_id, error_description, processed_on, processing_id, target) values (?, ?, ?, ?, ?)
.....
ERRORS:
SQL Error: 1048, SQLState: 23000
(conn=330108) Column 'dataset_id' cannot be null
Caused by: java.sql.SQLException: Column 'dataset_id' cannot be null
Query is: insert into bulk_sms_recipient (dataset_id, error_description, processed_on, processing_id, target) values (?, ?, ?, ?, ?), parameters [<null>,<null>,<null>,<null>,'+41788718818']
知道为什么会这样吗?为什么没有正确设置 dataset_id? id应该先插入bulk_sms_dataset,然后用auto_increment(MariaDB)生成的ID来设置bulk_sms_recipient的FK...
我把实体的代码放在下面。
@Entity
@Table(name = "bulk_sms_dataset")
@Data
@EqualsAndHashCode(exclude = "job")
public class BulkSmsDatasetEntity {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Long id;
@Column(name = "name")
private String name;
@Column(name = "template")
private String template;
@JoinColumn(name = "job_id")
@ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
private BulkSmsJobEntity job;
@OneToMany(mappedBy = "bulkSmsDatasetEntity", fetch = FetchType.LAZY)
@Cascade({org.hibernate.annotations.CascadeType.ALL})
private List<BulkSmsRecipientEntity> bulkSmsRecipientEntityList;
}
@Entity
@Table(name = "bulk_sms_recipient")
@Data
@EqualsAndHashCode(exclude = "bulkSmsDatasetEntity")
public class BulkSmsRecipientEntity {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Long id;
@Column(name = "target")
private String to;
@Column(name = "error_description")
private String error;
@Column(name = "processing_id")
private String processingId;
@Column(name = "processed_on", columnDefinition = "timestamp")
@Type(type = "org.hibernate.type.ZonedDateTimeType")
private ZonedDateTime processedOn;
@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "dataset_id", nullable = false)
private BulkSmsDatasetEntity bulkSmsDatasetEntity;
@OneToMany(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
@JoinColumn(name = "recipient_id")
private List<BulkSmsPlaceholderEntity> bulkSmsPlaceholderList;
}
【问题讨论】:
-
您可以尝试将 GenerationType 更改为 AUTO 而不是 IDENTITY 吗?我记得我一直在 MySQL 中使用那个类型,我只在 SQL Server 上使用了 IDENTITY
-
@vc73 我试过了,现在 Hibernate 似乎正在尝试使用 TABLE 生成模式。我得到了这个例外:
Table 'myschema.hibernate_sequence' doesn't exist -
您可能必须在您的休眠配置文件中设置
<prop key="hibernate.id.new_generator_mappings">false</prop>(来源:stackoverflow.com/questions/32968527/…) -
如果您使用 JPA,请改为设置
spring.jpa.properties.hibernate.id.new_generator_mappings=false -
OK,设置后,现在 AUTO 给出与 IDENTITY 相同的异常:
Caused by: java.sql.SQLException: Column 'dataset_id' cannot be null
标签: java mysql hibernate jpa mariadb