【发布时间】:2014-02-06 06:19:42
【问题描述】:
在 phtml 文件中将我的所有数据库显示在一个表中,包括 price、id 等,然后在 php 文件中 Details 当用户尝试按租金时,它会获取项目的 ID 并存储它在店里使用add的方法我一直收到这个错误
Fatal error: Function name must be a string.
我从数据库中存储项目 id 的原因是,当用户结帐时,我将使用用户选择的项目的 id 检索所有信息。而且我正在使用数组列表来存储一个以上的项目,要提到的另一件事是他们获取项目ID的方式是通过添加购物车文件中的局部变量$tem = $_POST(['$dvdDetails->getDvdId()']);,但我不确定它是否存储正确的值,因为有一个 foreach 循环,并且变量的持续时间将在方法结束时被扭曲,所以我怎样才能获得被选中项目的 id。
<?php
require_once('Models/Product.php');
class Shop {
private $_products = array();
public function getProducts()
{ return $this->_products;}
public function addProduct(Product $product)
{ $this->_products[] = $product;
return $this;
}
}
?>
<?php
class Option {
private $_optionKey;
private $_optionValue;
public function getKey()
{ return $this->_optionKey; }
public function getVlue()
{
return $this->_optionValue;
}
public function setOption($key, $value)
{
$this->_optionKey = $key;
$this->_optionValue = $value;
return $this;
}
}
?>
<?php
require_once('Models/Option.php');
class Product {
private $_options = array();
public function getOptions()
{ return $this->_options; }
public function addOption(Option $option)
{ $this->_options[] = $option;
return $this;
}
}
?>
//SHow all
<?php require('template/header.phtml') ?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<table class="datatable">
<tbody>
<?php foreach ($view->dd as $dvdDetails) {
echo '<tr> <td>'
.'<img src="images/'. $dvdDetails->getPhotoDetails() .'"alt="no picture" height="240" width="820" />' .'<br><br>'.'<font size="3" color="#2E2E2E"><center>'. $dvdDetails->getDvdPhoto(). '</center></font>'.
'<br><br><br>'. '<font size="2" color="blue"><strong>Genre: </strong></font>'. $dvdDetails->getDvdGenre() .
'<br><br>'. '<font size="2" color="blue"><strong>Director: </strong></font>'. $dvdDetails->getDvdDirector() . '<br><br>' .'<font size="2" color="blue"><strong>Ritels: </strong></font>'. $dvdDetails->getDvdRitels() .
'<br><br>' . '<font size="2" color="blue"><strong>Price for rent: </strong></font>'. $dvdDetails->getDvdId()) .
'<br><br>' .
'<div class="ghassar">' .
'<div id="op"> <label>Number of days </label> <select name="days" > <option>1</option> <option>2</option> <option>3</option> <option>4</option> <option>5</option>
</select>
<br><br><br><br>
</div>
<div>
<input type="submit" value="Add to the basket" name="rent" id="buttom1" />
</div> ' . '<br><br>' .
'<br><br>' .'<div>'.
'</td> </td> </tr>';
} ?>
</tbody>
</table>
<?php require('template/footer.phtml') ?>
//加入购物车
<?php
require_once('Models/Dvd_sql.php');
require_once('Models/Shop.php');
$view = new stdClass();
$view->dd = 'SQL';
$dvd_sql = new Dvd_sql();
$view->dd = $dvd_sql->fetchAllStudents(); //->fetchAllStudents();
if (isset($_POST['rent']))
{
$tem = $_POST(['$dvdDetails->getDvdId()']);
$shop = new Shop(); $shop->addProduct($tem);
}
require_once('Views/dvdDetails.phtml');
【问题讨论】:
标签: php html mysql arrays post