如何在mysql和spring-boot中将tinyint映射到整数？

Question

我从spring-boot-2.4.5升级到spring-boot-2.5.0。

由于从 mariadb-java-client-2.7.2 升级到 mariadb-java-client-2.7.3 会出现此问题。但我不知道为什么，我不知道这更多的是休眠还是 mariadb 连接器问题。

现在我的应用程序启动失败：

found [bit (Types#TINYINT)], but expecting [tinyint unsigned (Types#INTEGER)]

我已将该列声明为Integer 类型的@Column("TINYINT")，而在mysql 中它是一个真正的tinyint，在升级之前它可以正常工作！

@Column(columnDefinition = "TINYINT")
public Integer counter;
    
    
CREATE TABLE foo {
    ... 
    counter tinyint NOT NULL,
    ...
}

我能做什么？为什么突然不支持tinyint了？

完整日志：

Caused by: org.hibernate.tool.schema.spi.SchemaManagementException: Schema-validation: wrong column type encountered in column [count] in table [foo]; found [bit (Types#TINYINT)], but expecting [tinyint unsigned (Types#INTEGER)]
    at org.hibernate.tool.schema.internal.AbstractSchemaValidator.validateColumnType(AbstractSchemaValidator.java:159) ~[hibernate-core-5.4.32.Final.jar:5.4.32.Final]
    at org.hibernate.tool.schema.internal.AbstractSchemaValidator.validateTable(AbstractSchemaValidator.java:143) ~[hibernate-core-5.4.32.Final.jar:5.4.32.Final]
    at org.hibernate.tool.schema.internal.GroupedSchemaValidatorImpl.validateTables(GroupedSchemaValidatorImpl.java:42) ~[hibernate-core-5.4.32.Final.jar:5.4.32.Final]
    at org.hibernate.tool.schema.internal.AbstractSchemaValidator.performValidation(AbstractSchemaValidator.java:89) ~[hibernate-core-5.4.32.Final.jar:5.4.32.Final]
    at org.hibernate.tool.schema.internal.AbstractSchemaValidator.doValidation(AbstractSchemaValidator.java:68) ~[hibernate-core-5.4.32.Final.jar:5.4.32.Final]
    at org.hibernate.tool.schema.spi.SchemaManagementToolCoordinator.performDatabaseAction(SchemaManagementToolCoordinator.java:192) ~[hibernate-core-5.4.32.Final.jar:5.4.32.Final]
    at org.hibernate.tool.schema.spi.SchemaManagementToolCoordinator.process(SchemaManagementToolCoordinator.java:73) ~[hibernate-core-5.4.32.Final.jar:5.4.32.Final]
    at org.hibernate.internal.SessionFactoryImpl.<init>(SessionFactoryImpl.java:318) ~[hibernate-core-5.4.32.Final.jar:5.4.32.Final]
    at org.hibernate.boot.internal.SessionFactoryBuilderImpl.build(SessionFactoryBuilderImpl.java:468) ~[hibernate-core-5.4.32.Final.jar:5.4.32.Final]
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:1259) ~[hibernate-core-5.4.32.Final.jar:5.4.32.Final]
    at org.springframework.orm.jpa.vendor.SpringHibernateJpaPersistenceProvider.createContainerEntityManagerFactory(SpringHibernateJpaPersistenceProvider.java:58) ~[spring-orm-5.3.8.jar:5.3.8]
    at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:365) ~[spring-orm-5.3.8.jar:5.3.8]
    at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.buildNativeEntityManagerFactory(AbstractEntityManagerFactoryBean.java:409) ~[spring-orm-5.3.8.jar:5.3.8]
    at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:396) ~[spring-orm-5.3.8.jar:5.3.8]
    at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.afterPropertiesSet(LocalContainerEntityManagerFactoryBean.java:341) ~[spring-orm-5.3.8.jar:5.3.8]
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1845) ~[spring-beans-5.3.8.jar:5.3.8]
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1782) ~[spring-beans-5.3.8.jar:5.3.8]
    ... 21 more

Answer 1

将代码修改为：

@Column(columnDefinition = "TINYINT")
@Type(type = "org.hibernate.type.IntegerType")
public Integer counter;