Mysql查询加入条件不起作用

Question

我有一种情况，我需要通过加入table_1、table_2、table_3、table_6来获取数据，下面是代表我需要放在查询下方的所有条件的查询，效果很好并获得完美的数据

查询 1

SELECT   table_1.id                                                   
AS id1,   table_1.deal_id                                             
AS deal_id5,   CONVERT_TZ(table_1.due_date, 'UTC', 'EST')             
AS sclr20,   table_2.deal_name                                        
AS deal_name22 FROM  table_1   INNER JOIN  table_2 ON (table_1.deal_id
= table_2.deal_id)   INNER JOIN  table_3 ON (table_1.id = table_3.child_bwic_id)   INNER JOIN  table_6 ON (table_6.id =
table_3.bwic_id)

WHERE table_6.data_source_id <> 2
      AND table_1.status IN (1, 2, 3)
      AND DATE(table_1.due_date) = '2015-08-13'

GROUP BY table_1.deal_id, sclr20 ORDER BY sclr20 ASC, id1 ASC;

现在由于某些要求，我需要再添加一张表到条件table_4，并检查table_4 中是否存在记录，然后标记它，因此我编写查询以左连接table_4 为：

查询 2

SELECT   table_1.id                                                   
AS id1,   table_1.deal_id                                             
AS deal_id5,   CONVERT_TZ(table_1.due_date, 'UTC', 'EST')             
AS sclr20,   table_2.deal_name                                        
AS deal_name22,   if(table_4.id IS NULL, 'public', 'private')         
AS sclr51

FROM child_bwic table_1   INNER JOIN deal table_2 ON (table_1.deal_id
= table_2.deal_id)   INNER JOIN bwic_child_association table_3 ON (table_1.id = table_3.child_bwic_id)   INNER JOIN bwic table_6 ON
(table_6.id = table_3.bwic_id)

  LEFT JOIN bwic_private_group_association table_4 ON table_6.id =
table_4.bwic_id

WHERE table_6.data_source_id <> 2
      AND table_1.status IN (1, 2, 3)
      AND DATE(table_1.due_date) = '2015-08-13'

GROUP BY table_1.deal_id, sclr20 ORDER BY sclr20 ASC, id1 ASC;

这个也很好用并且给出了正确的结果集

要进一步深入研究结果，我需要将table_4 与table_5 一起加入，这样我就可以将结果限制在特定用户的组中。所以我把查询写成：

查询 3

SELECT

  table_1.id                                                          
AS id1,   table_1.deal_id                                             
AS deal_id5,   CONVERT_TZ(table_1.due_date, 'UTC', 'EST')             
AS sclr20,   table_2.deal_name                                        
AS deal_name22,   if(table_4.id IS NULL, 'public', 'private')         
AS sclr51 FROM child_bwic table_1   INNER JOIN deal table_2 ON
(table_1.deal_id = table_2.deal_id)   INNER JOIN
bwic_child_association table_3 ON (table_1.id = table_3.child_bwic_id)
INNER JOIN bwic table_6 ON (table_6.id = table_3.bwic_id)


  LEFT JOIN bwic_private_group_association table_4 ON table_6.id =
table_4.bwic_id   JOIN bwic_private_group_user_association table_5 ON
table_4.group_id = table_5.group_id AND table_5.user_id = 1512

WHERE table_6.data_source_id <> 2
      AND table_1.status IN (1, 2, 3)
      AND DATE(table_1.due_date) = '2015-08-13'

GROUP BY table_1.deal_id, sclr20 ORDER BY sclr20 ASC, id1 ASC;

但如果我在查询 2 中得到的 table_4（公共记录）中不存在记录，则此查询不会返回结果。

我不想将查询 1 的联接结果与table_4 和table_5 的内部联接分开。

任何帮助将不胜感激。

编辑：

还忘了提到我正在使用 Doctrine Query Builder。所以我没有子查询的选项。我已简化此查询以避免显示 Doctrine QB 实现。

Answer 1

我不确定，但这应该可以工作，而不是经过测试。

SELECT

  table_1.id
    AS id1,
  table_1.deal_id
    AS deal_id5,
  CONVERT_TZ(table_1.due_date, 'UTC', 'EST')
    AS sclr20,
  table_2.deal_name
    AS deal_name22,
  if(table_4.id IS NULL, 'public', 'private')
    AS sclr51
FROM child_bwic table_1
  INNER JOIN deal table_2 ON (table_1.deal_id = table_2.deal_id)
  INNER JOIN bwic_child_association table_3 ON (table_1.id = table_3.child_bwic_id)
  INNER JOIN bwic table_6 ON (table_6.id = table_3.bwic_id)


  LEFT JOIN bwic_private_group_association table_4 ON table_6.id = table_4.bwic_id
  left JOIN bwic_private_group_user_association table_5 ON table_4.group_id = table_5.group_id

WHERE table_6.data_source_id <> 2
      AND table_1.status IN (1, 2, 3)
      AND DATE(table_1.due_date) >= '2015-08-19'
      and (table_5.user_id = 1512 or table_5.user_id is NULL )
GROUP BY table_1.deal_id, sclr20
ORDER BY sclr20 ASC, id1 ASC;

我所做的是我离开加入 table_5 保持条件 table_5.user_id = 1512 or table_5.user_id is NULL 这样您将只获得用户 1512 数据以及不在 table5 和 table4 中的数据。

希望对你有帮助。

Answer 2

执行此操作的一种方法是创建一个内联视图，该视图首先连接表 4 和 5，然后连接回您的基本集...我将结果别名为“B”，然后更新外部选择以使用 B。 ID 并将左连接的 on 条件更新为 ON table_6.id = B.bwic_id

为什么这样做是引擎必须首先解析子选择，然后再发生左连接。使用这种方法，由于左连接之后的内连接，左连接被否定。

在MsACCESS()'s 中可以在joins 周围添加来指示join 操作的顺序。 mySQL 可能也支持这个，我只是没用过。

理想情况下，您可以将表 4 和表 5 的 * 替换为您感兴趣的字段列表。如果表 4 和表 5 都具有外部选择中引用的 ID 字段，则需要这样做。

SELECT
  table_1.id AS id1,   
  table_1.deal_id AS deal_id5,   
  CONVERT_TZ(table_1.due_date, 'UTC', 'EST') AS sclr20,   
  table_2.deal_name AS deal_name22,   
  if(B.id IS NULL, 'public', 'private') AS sclr51 

FROM child_bwic table_1   
INNER JOIN deal table_2 
 ON table_1.deal_id = table_2.deal_id
INNER JOIN bwic_child_association table_3 
  ON table_1.id = table_3.child_bwic_id
INNER JOIN bwic table_6 
  ON (table_6.id = table_3.bwic_id)
LEFT JOIN 
 (SELECT * 
  FROM bwic_private_group_association table_4 
  INNER JOIN bwic_private_group_user_association table_5 
    ON table_4.group_id = table_5.group_id 
   AND table_5.user_id = 1512) B
  ON table_6.id = B.bwic_id   

WHERE table_6.data_source_id <> 2
      AND table_1.status IN (1, 2, 3)
      AND DATE(table_1.due_date) = '2015-08-13'
GROUP BY table_1.deal_id, sclr20 ORDER BY sclr20 ASC, id1 ASC;