通过 php(CodeIgniter) 中的给定数组从 mysql 表中选择列。

Question

我想从我选择名称作为输入值的 mysql 表中选择列。在我看来，必须选择列名作为多个输入字段。在此选择选项中，值等于数据库中我的“pass_due”表中的列名。

<form id=""  name=" Passdue "  action="<?=base_url('index.php/Passdue_ctrl/select')?>" method="post">
<div >
     <input class="date-picker" id="report_date" name="report_date"   value="" placeholder="Select Date"/>
     <select multiple="" class="chzn-select" id=" " data-placeholder="Select sections " name="table_feilds">
                           <option value="" />
                           <option value="below_1" /> Below month
                           <option value="month_1_3" /> Month 1-3
                           <option value="month_3_6" /> Month 3-6
                            <option value="month_6_9" /> Month 6-9
                            <option value="over_9" /> Over 9 month
      </select>
</div>
<div>
            <button type="submit" class="btn btn-mini btn-info">Submit</button> 
              <button type="reset" id="reset" class="btn btn-mini btn-info">Reset</button>
</div>   
</form>

这是我的控制器中的功能

Function select (){
$fld_name =$this->input->post('table_feilds');
$reportdate=$this->input->post('report_date');
$report=$this->Passdue_model->get_report_part($fld_name,$reportdate);
If($report){
$this->data['report_part']=$report;
$this->data['fld_name']=$fld_name;
$this->load->view('Passdue_other_view',$this->data);
}
}

在我的模型中是这样的。

function get_report_part1($fld_name,$reportdate)
    {
$this->db->select($fld_name);
$this->db->from(‘pass_due’);
$this->db->where('fld_actORinact_date <=',$reportdate);
        	$query = $this->db->get();
        		if($query){
           		 return $query->result();
        		}
   }

当我运行此代码时，它会从表中选择所有列，而不仅仅是选定的列。它还显示错误为 为 foreach() 提供的参数无效。

Answer 1

您可以使用这个新的模型方法从您的数据库中检索数据。所以将此方法插入您的模型中

function getDetail($tablename = '', $columns_arr = array(), $where_arr = array(), $limit = 0, $offset = 0)
{
    $limit = ($limit == 0) ? Null : $limit;

    if (!empty($columns_arr)) {
        $this->db->select(implode(',', $columns_arr), FALSE);
    }

    if ($tablename == '') {
        return array();
    } else {
        $this->db->from($tablename);

        if (!empty($where_arr)) {
            $this->db->where($where_arr);
        }

        if ($limit > 0 AND $offset > 0) {
            $this->db->limit($limit, $offset);
        } elseif ($limit > 0 AND $offset == 0) {
            $this->db->limit($limit);
        }

        $query = $this->db->get();

        return $query->result();
    }
}
//These are include within controller methods

$fld_name =$this->input->post('table_feilds');
//you have to send your columns from your multiple select object as array.
//create column array
$arr_columns=array();
for($i=0,$i<=count($fld_name);$i++){
$arr_columns=array_push($fld_name)
}
$reportdate=$this->input->post('report_date');
 //create where array
$arr_where=array('fld_actORinact_date <=' => $reportdate);
//retreive data
$datatable=‘pass_due’;
   $report=$this->Passdue_model->getDetail($datatable,$arr_columns,$arr_where,0,0);
var_dump($report);

//finally dump_data set .it return array object.Then loop retrieved object.

那么这将返回您所期望的。 还想建议您使用通用模型，除了为每个表使用单独的模型。

Answer 2

use below code in form

    <select multiple="multiple" class="chzn-select" id=" " data-placeholder="Select sections " name="table_feilds[]">  <!-- use [] for multiple values --> 

and I don't see any foreach loop?

and first 
echo '<pre>';print_r($fld_name);exit; before 
$report=$this->Passdue_model->get_report_part($fld_name,$reportdate);

Answer 3

在您的模型中返回如下查询

return $query->result_array();

在你的控制器中获取数据

data['fld_name']=$this->Passdue_model->get_report_part($fld_name,$reportdate);
$this->load->view('Passdue_other_view',$data);

在您的查看页面中

foreach($fld_name as $fld_name){?> <th><?php echo $fld_name['column_name '];?></th> <?php }?> </tr> </thead>