查找相同的提供者 ID 并合并为一个，并将相同提供者 ID 的服务合并到一个提供者对象数组中答案

【问题标题】：Find same Provider Ids and merge into one and also merge services of same provider id in one Array of Provider Object查找相同的提供者 ID 并合并为一个，并将相同提供者 ID 的服务合并到一个提供者对象数组中
【发布时间】：2020-08-29 06:38:40
【问题描述】：

{
    "success": true,
    "message": "successfully retrieved",
    "data": [
        {
            "providerId": 826172,
            "profile": null,
            "service": {
                "id": 1,
                "name": "Hair Cutting",
                "description": "This is to cut hairs",
                "serviceThumbnail": null,
                "defaultPriceInAED": 20,
                "defaultDurationInMin": 30
            }
        },
        {
            "providerId": 826173,
            "profile": null,
            "service": {
                "id": 2,
                "name": "Hair Coloring",
                "description": "This is to color hairs",
                "serviceThumbnail": null,
                "defaultPriceInAED": 20,
                "defaultDurationInMin": 30
            }
        },
        {
            "providerId": 826173,
            "profile": null,
            "service": {
                "id": 3,
                "name": "Nail Cutting",
                "description": "This is for Nail cutting service",
                "serviceThumbnail": null,
                "defaultPriceInAED": 20,
                "defaultDurationInMin": 30
            }
        }
    ]
}

【问题讨论】：

请向我们展示您的尝试
感谢评论问题已解决:)
我需要相同的提供者 ID 服务对象将合并到一个对象中

标签： javascript mysql node.js json api

【解决方案1】：

您的问题很不清楚，您想要实现什么。似乎您想将providerId 及其数据分组（如果相同）。如果是这样，你可以试试这个：

var value = { "success": true, "message": "successfully retrieved", "data": [ { "providerId": 826172, "profile": null, "service": { "id": 1, "name": "Hair Cutting", "description": "This is to cut hairs", "serviceThumbnail": null, "defaultPriceInAED": 20, "defaultDurationInMin": 30 } }, { "providerId": 826173, "profile": null, "service": { "id": 2, "name": "Hair Coloring", "description": "This is to color hairs", "serviceThumbnail": null, "defaultPriceInAED": 20, "defaultDurationInMin": 30 } }, { "providerId": 826173, "profile": null, "service": { "id": 3, "name": "Nail Cutting", "description": "This is for Nail cutting service", "serviceThumbnail": null, "defaultPriceInAED": 20, "defaultDurationInMin": 30 } }, { "providerId": 826173, "profile": null, "service": { "id": 3, "name": "Nail Cutting 5", "description": "This is for Nail cutting service", "serviceThumbnail": null, "defaultPriceInAED": 20, "defaultDurationInMin": 30 } } ]};

var result = value.data.reduce((acc, elem)=>{
 getIndex = acc.findIndex(val=>val.providerId==elem.providerId);
 getIndex==-1 ?  (elem.service=[elem.service], acc.push(elem)) : acc[getIndex].service = [elem.service, ...acc[getIndex].service]
return acc; 
},[]);

console.log(result);

我希望它有所帮助。谢谢！

【讨论】：

谢谢你帮我节省时间

【解决方案2】：

var value = { "success": true, "message": "successfully retrieved", "data": [ { "providerId": 826172, "profile": null, "service": { "id": 1, "name": "Hair Cutting", "description": "This is to cut hairs", "serviceThumbnail": null, "defaultPriceInAED": 20, "defaultDurationInMin": 30 } }, { "providerId": 826173, "profile": null, "service": { "id": 2, "name": "Hair Coloring", "description": "This is to color hairs", "serviceThumbnail": null, "defaultPriceInAED": 20, "defaultDurationInMin": 30 } }, { "providerId": 826173, "profile": null, "service": { "id": 3, "name": "Nail Cutting", "description": "This is for Nail cutting service", "serviceThumbnail": null, "defaultPriceInAED": 20, "defaultDurationInMin": 30 } }, { "providerId": 826173, "profile": null, "service": { "id": 3, "name": "Nail Cutting 5", "description": "This is for Nail cutting service", "serviceThumbnail": null, "defaultPriceInAED": 20, "defaultDurationInMin": 30 } } ]};

var result = value.data.reduce((acc, elem)=>{
 getIndex = acc.findIndex(val=>val.providerId==elem.providerId);
 getIndex==-1 ?  (elem.service=[elem.service], acc.push(elem)) : acc[getIndex].service = [elem.service, ...acc[getIndex].service]
return acc; 
},[]);

console.log(result);

【讨论】：