获取重复的sql结果

Question

我有 3 个表：Users、Articles 和 Votes

| Users |    | Articles |    |   Votes   |
|   id  |    |    id    |    |  userId   |
|  name |    |  title   |    | articleId |
| email |    |  userId  |    |    type   |

我想获得每个用户的 Count voteup 和 Count votedown 用户列表。

我正在测试这个查询：

SELECT u.id,u.name,u.email,
(SELECT COUNT(*) FROM votes as v WHERE v.type=1 AND v.articleId IN 
   (SELECT a.id From articles as a WHERE a.userId = u.id) ) AS totalvoteup,
(SELECT COUNT(*) FROM votes as v WHERE v.type=0 AND v.articleId IN 
   (SELECT a.id From articles as a WHERE a.userId = u.id) ) AS totalvotedown
FROM users as u

当我通过 phpmyadmin 测试它时，我有我想要的列表（结果数与表中的用户数匹配），但是当我尝试通过节点服务器（来自 AngularJs 或 Postman）时，我得到了重复结果：

{
"users": [
[
  {
    "id": 1,
    "name": "John Lennon",
    "email": "johnlennon@gmail.com",
    "totalvoteup": 0,
    "totalvotedown": 0
  },
  {
    "id": 2,
    "name": "John Lennon 2",
    "email": "johnlennon2@gmail.com",
    "totalvoteup": 0,
    "totalvotedown": 0
  },
  {
    "id": 3,
    "name": "John Lennon 3",
    "email": "johnlennon3@gmail.com",
    "totalvoteup": 0,
    "totalvotedown": 1
  },
  {
    "id": 4,
    "name": "John Lennon 4",
    "email": "johnlennon4@gmail.com",
    "totalvoteup": 0,
    "totalvotedown": 0
  }
],
[
  {
    "id": 1,
    "name": "John Lennon 1",
    "email": "johnlennon1@gmail.com",
    "totalvoteup": 0,
    "totalvotedown": 0
  },
  {
    "id": 2,
    "name": "John Lennon 2",
    "email": "johnlennon2@gmail.com",
    "totalvoteup": 0,
    "totalvotedown": 0
  },
  {
    "id": 3,
    "name": "John Lennon 3",
    "email": "johnlennon3@gmail.com",
    "totalvoteup": 0,
    "totalvotedown": 1
  },
  {
    "id": 4,
    "name": "John Lennon 4",
    "email": "johnlennon4@gmail.com",
    "totalvoteup": 0,
    "totalvotedown": 0
  }
]
]
}

任何想法如何解决这个问题？

Answer 1

我不是 Java 人，不确定问题所在，但查询可以用更好的方式编写

SELECT DISTINCT u.id,
       u.name,
       u.email,
       coalesce(totalvoteup,0) as totalvoteup,
       coalesce(totalvotedown,0) as totalvotedown
FROM   users AS u
       LEFT JOIN (SELECT DISTINCT id,userId FROM articles) a
              ON a.userId = u.id
       LEFT JOIN (SELECT Count(CASE WHEN v.type = 1 THEN 1 END) AS totalvoteup,
                         Count(CASE WHEN v.type = 0 THEN 1 END) AS totalvotedown,
                         v.articleId
                  FROM   votes v
                  GROUP  BY v.articleId) v
              ON a.id = v.articleId 

由于我喜欢查询优化，可能无法帮助您解决刚刚想到分享的问题