【发布时间】:2020-07-29 06:05:49
【问题描述】:
我写了下面的MYSQL查询,Mysql版本是8.0.18-commercial
SELECT p.server, 'Type_ABC' AS Check_Type, COALESCE(vmtable.res) AS result
FROM server p
INNER JOIN truns t ON t.oq_id = p.oq_id
AND t.id = (SELECT t2.id FROM truns t2 WHERE t2.oq_id = p.oq_id order by t2.created_at desc limit 1 )
INNER JOIN qvuln_info vmtable ON vmtable.run_id = t.id
LEFT JOIN qvuln_info_data vmtableinfo ON vmtableinfo.qid = vmtable.qid
WHERE p.server regexp 'server1';
我从上述查询中得到以下输出:
Hostname Check_Type result
server1 Type_ABC Result 1
server1 Type_ABC Result 2
server1 Type_ABC Result 3
server1 Type_ABC Result 4
我想连接结果,以便输出如下所示:
Hostname Check_Type result
server1 Type_ABC Result 1,,Result 2,,Result 3,,Result 4
为了实现上述输出,我编写了以下查询,但它给出了语法错误:
SELECT p.server, 'Type1' AS Check_Type,
GROUP_CONCAT((COALESCE(vmtable.res) AS result) SEPARATOR ', ')
FROM server p
INNER JOIN truns t ON t.oq_id = p.oq_id
AND t.id = (SELECT t2.id FROM truns t2 WHERE t2.oq_id = p.oq_id order by t2.created_at desc limit 1 )
INNER JOIN qvuln_info vmtable ON vmtable.run_id = t.id
LEFT JOIN qvuln_info_data vmtableinfo ON vmtableinfo.qid = vmtable.qid
WHERE p.server regexp 'server1';
如何正确使用GROUP_CONCAT和COALESCE?
【问题讨论】:
标签: mysql join select inner-join coalesce