使用 CONCAT() 的 SELECT 语句和使用 CONCAT() 的 WHERE

Question

我想用这个语句在 MySQL 中构建一个查询：

SELECT CONCAT(students.FirstName, ' ', students.LastName) AS FullName FROM `students` WHERE CONCAT(students.FirstName, ' ', students.LastName)LIKE '%John%'

现在，我使用 Laravel 的 Query Builder，我可以使用 CONCAT() 匹配列。这是我的代码供参考：

    public function getStudent(Request $request)
    {
        $fullName = Student::select(FacadesDB::raw('SELECT CONCAT(LastName, ", ", FirstName) AS FullName'), )
            ->where(FacadesDB::raw('CONCAT(LastName, ", ", FirstName)', 'LIKE', "'% {{ $request->terms }} %'"))
            ->get();
        return response()->json($fullName);
    }

当我尝试运行代码时，我得到了这样的结果：

SQLSTATE[42000]: 语法错误或访问冲突：1064 您的 SQL 语法有错误；检查与您的 MariaDB 服务器版本相对应的手册，以在第 1 行的 'SELECT CONCAT(LastName, ", ", FirstName) AS FullName from students where CO...' 附近使用正确的语法（SQL：选择 SELECT CONCAT (LastName, ", ", FirstName) AS FullName from students where CONCAT(LastName, ", ", FirstName) is null)

有没有一种方法可以实现这一目标？我花了将近 4 个小时来解决此代码，但我仍然无法解决它。每一个帮助将不胜感激。顺便说一句，我是 Laravel 的新用户。

Answer 1

你可以使用地图功能：-

Student::select("firstname","lastname")
->where("firstname","like","%john%")
->orWhere("lastname","like","%john%")
->get()->map(function($query){
    $fullname = $query->firstname." ".$query->lastname
    return ["fullname" => $fullname]
 })

Answer 2

我会保持简单，只需将您的查询表述为：

SELECT CONCAT(FirstName, ' ', LastName) AS FullName
FROM students
WHERE FirstName LIKE '%John%' OR LastName LIKE '%John%';

更新的 Laravel 代码：

public function getStudent(Request $request)
{
    $fullName = Student::select(FacadesDB::raw('CONCAT(LastName, ", ", FirstName) AS FullName'), )
        ->where(FirstName, 'LIKE', '%John%')
        ->orWhere(LastName, 'LIKE', '%John%')
        ->get();
    return response()->json($fullName);
}