【发布时间】:2015-07-22 05:53:07
【问题描述】:
我正在使用 JPA 开发我的第一个项目,使用 MySQL 作为我的数据库和 Hibernate 4.3.8 作为 Spring 4 Web 项目中的 JPA 提供程序。
在我的 Spring 配置中,我设置了数据库和方言:
HibernateJpaVendorAdapter hjpaVA = new HibernateJpaVendorAdapter();
hjpaVA.setDatabase(Database.MYSQL);
hjpaVA.setDatabasePlatform("org.hibernate.dialect.MySQL5Dialect");
我试图得到这个给我带来麻烦的查询:
TypedQuery<KundeDTO> query = entityManager.createQuery("select new zdb.dto.KundeDTO(k.id, k.firma.firmenname, k.regnr, k.kategorie)
from Kunde k where k.id = :id", KundeDTO.class);
这是 Hibernate 生成的 SQL:
select kunde0_.`id` as col_0_0_, firma1_.`firmenname` as col_1_0_, kunde0_.`regnr` as col_2_0_, kunde0_.id_kategorie as col_3_0_
from `zdb_e`.`Kunde` kunde0_, `zdb_e`.`Firma` firma1_
inner join `zdb_e`.`Kategorie` kategorie2_ on kunde0_.id_kategorie=kategorie2_.`id`
where kunde0_.id_firma=firma1_.`id` and kunde0_.`id`=1;
注意,内连接上没有括号!
运行此语句会导致以下错误:
com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException:
Unknown column 'kunde0_.id_kategorie' in 'on clause'
这里详细说明了异常的原因: mysql-unknown-column-in-on-clause
当我将括号添加到 where 和内部连接子句并直接针对数据库运行该语句时,它可以工作:
select kunde0_.`id` as col_0_0_, firma1_.`firmenname` as col_1_0_, kunde0_.`regnr` as col_2_0_, kunde0_.id_kategorie as col_3_0_
from (`zdb_e`.`Kunde` kunde0_, `zdb_e`.`Firma` firma1_ )
inner join `zdb_e`.`Kategorie` kategorie2_ on
( kunde0_.id_kategorie=kategorie2_.`id` )
where kunde0_.id_firma=firma1_.`id` and kunde0_.`id`=1;
那么,我怎样才能说服 Hibernate 生成这样的查询呢?
更新:这里是实体
昆德
@Entity
public class Kunde implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue
private Integer id;
private Integer regnr;
@OneToOne(optional=false)
@JoinColumn(name="id_firma", nullable = false)
private Firma firma;
@OneToOne(optional=false)
@JoinColumn(name="id_kategorie", nullable = false)
private Kategorie kategorie;
@OneToOne(optional=false)
@JoinColumn(name="id_lieferregion", nullable = false)
private Lieferregion lieferregion;
// getters and setters....
}
公司
@Entity
@Table(name = "Firma")
public class Firma implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue
private Integer id;
@Column(name="firmenname")
private String firmenname;
@Column(name="uid")
private String uid;
@OneToOne(optional=false)
@JoinColumn(name="id_anschrift", nullable = false)
private Anschrift anschrift;
@OneToMany(mappedBy="id_firma", fetch=FetchType.EAGER)
private List<Person> personen;
public Firma() {
personen = new ArrayList<Person>();
}
// getters and setters....
}
类别
@Entity
public class Kategorie implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue
private Integer id;
private Integer nummer;
private String bezeichnung;
public Kategorie() {
}
public Kategorie(int kategorieId, int kategorieNummer, String kategorieBezeichnung) {
this.id = kategorieId;
this.nummer = kategorieNummer;
this.bezeichnung = kategorieBezeichnung;
}
// getters and setters....
}
数据库架构
CREATE TABLE kategorie
(id INTEGER NOT NULL AUTO_INCREMENT,
nummer INTEGER NOT NULL,
bezeichnung VARCHAR(100) NOT NULL,
PRIMARY KEY (id),
UNIQUE (nummer, bezeichnung)
);
CREATE TABLE firma
(ID INTEGER NOT NULL AUTO_INCREMENT,
firmenname VARCHAR(50) NOT NULL,
uid VARCHAR(20) NOT NULL,
url VARCHAR(100) NOT NULL,
id_anschrift INTEGER NOT NULL,
id_logo INTEGER,
PRIMARY KEY (id),
UNIQUE (uid),
UNIQUE (firmenname),
UNIQUE (id_anschrift),
CONSTRAINT firma_fk1 FOREIGN KEY (id_anschrift) REFERENCES ANSCHRIFT (ID),
CONSTRAINT firma_fk2 FOREIGN KEY (id_logo) REFERENCES logo (ID));
CREATE TABLE kunde
(id INTEGER NOT NULL AUTO_INCREMENT,
regnr INTEGER NOT NULL,
id_kategorie INTEGER NOT NULL,
id_firma INTEGER NOT NULL,
id_benutzer INTEGER,
id_lieferregion INTEGER NOT NULL,
PRIMARY KEY (id),
UNIQUE (regnr, id_kategorie),
UNIQUE (id_firma),
UNIQUE (id_benutzer),
CONSTRAINT kunde_fk1 FOREIGN KEY (id_firma) REFERENCES firma (id),
CONSTRAINT kunde_fk2 FOREIGN KEY (id_benutzer) REFERENCES benutzer (id),
CONSTRAINT kunde_fk3 FOREIGN KEY (id_kategorie) REFERENCES kategorie (id),
CONSTRAINT kunde_fk4 FOREIGN KEY (id_lieferregion) REFERENCES lieferregion (id)
);
进一步测试
问题在于 from 子句中缺少括号。
直接针对数据库:
select k.id, k.regnr, f.firmenname from (Kunde k, Firma f) JOIN kategorie kat on k.id_kategorie = kat.id where k.id = 1 and k.id_firma = f.id;
有效!
select k.id, k.regnr, f.firmenname from Kunde k, Firma f JOIN kategorie kat on k.id_kategorie = kat.id where k.id = 1 and k.id_firma = f.id;
不起作用:“on 子句”中的未知列“k.id_kategorie”
为什么我什至需要在 from 子句上加上括号?
我怎样才能让 Hibernate 把它们放进去?
【问题讨论】:
-
该错误与您链接的错误不同。查询中的 ON 子句后面没有
AND,并且该错误清楚地说明了不存在的列。检查您的数据库架构。 -
@JBNizet OP 说当他添加括号时该语句有效......强烈暗示列确实存在。
-
粘贴您的昆德语和类别课程。你也可以这样尝试“select new zdb.dto.KundeDTO(k.id, k.firma.firmenname, k.regnr, kat) from Kunde k JOIN k.kategorie kat where k.id = :id”跨度>
-
@JBNizet 架构似乎正确,所有列都存在。
-
@jgr 试过了。 (相应地编辑了我的问题)问题是 from 子句上的括号。
标签: java mysql spring hibernate jpa