【发布时间】:2018-12-04 07:23:22
【问题描述】:
我正在尝试更新类型化 XML 中的属性。我过去通过在非类型化对象中构建 XML 然后将其设置为类型化对象来完成此操作(因此避免了这个问题),但我想知道如何直接修改类型化数据。
我的架构是:
if exists (select [xml_collection_id]
from sys.[xml_schema_collections] as [xsc]
where [xsc].name = 'xsc_test_stack'
and [xsc].[schema_id] = schema_id(N'chamomile'))
drop xml schema collection [chamomile].[xsc_test_stack];
go
create xml schema collection [chamomile].[xsc_test_stack] as N'<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:chamomile="https://github.com/KELightsey/chamomile" targetNamespace="https://github.com/KELightsey/chamomile">
<xsd:element name="test_stack">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="description" type="xsd:string" minOccurs="1" maxOccurs="1" />
<xsd:element name="test_stack_detail" type="chamomile:any_complex_type" minOccurs="0" maxOccurs="unbounded" />
<xsd:element name="test" type="chamomile:any_complex_type" minOccurs="0" maxOccurs="unbounded" />
</xsd:sequence>
<xsd:attribute name="name" type="xsd:string" use="required" />
<xsd:attribute name="test_count" type="xsd:int" use="required" />
<xsd:attribute name="pass_count" type="xsd:int" use="required" />
<xsd:attribute name="timestamp" type="xsd:dateTime" use="required" />
<xsd:anyAttribute processContents="lax" />
</xsd:complexType>
</xsd:element>
<xsd:complexType name="any_complex_type">
<xsd:complexContent>
<xsd:restriction base="xsd:anyType">
<xsd:sequence>
<xsd:any minOccurs="0" maxOccurs="unbounded" processContents="lax"/>
</xsd:sequence>
<xsd:anyAttribute processContents="lax" />
</xsd:restriction>
</xsd:complexContent>
</xsd:complexType>
</xsd:schema>';
go
我构建的结构类型示例如下:
declare @test [xml]([chamomile].[xsc_test_stack]) = N'
<chamomile:test_stack xmlns:chamomile="https://github.com/KELightsey/chamomile" name="[chamomile].[person_test].[get_age]" test_count="2" pass_count="2" timestamp="2018-06-24T15:50:19.3466667">
<description>This test stack consists of tests which validate the functionality of the age calculation for a person.</description>
</chamomile:test_stack>';
go
declare @test [xml]([chamomile].[xsc_test_stack]) = N'
<chamomile:test_stack xmlns:chamomile="https://github.com/KELightsey/chamomile" name="[chamomile].[person_test].[get_age]" test_count="2" pass_count="2" timestamp="2018-06-24T15:50:19.3466667">
<description>This test stack consists of tests which validate the functionality of the age calculation for a person.</description>
<test_stack_detail>
<any_valid_xml_goes_here />
</test_stack_detail>
</chamomile:test_stack>';
go
我尝试过的是:
set @test_stack.modify(N'replace value of (//@test_count)[1] with sql:variable("@count")');
返回:Msg 9306, Level 16, State 1, Line 28 XQuery [modify()]: 'replace value of' 的目标不能是联合类型,找到 '(attribute(test_count,xs:int) | attribute(test_count,xs:anySimpleType)) ?'。
set @test_stack.modify(N'declare namespace chamomile="https://github.com/KELightsey/chamomile";
replace value of (chamomile:test_stack/@test_count)[1] with sql:variable("@count")');
返回:Msg 9306, Level 16, State 1, Line 25 XQuery [modify()]: 'replace value of' 的目标不能是联合类型,找到 '(attribute(test_count,xs:int) | attribute(test_count,xs:anySimpleType)) ?'。
我花了几个小时在 Google 上挖掘这个。无类型 XML 的示例有很多很多,而有类型 XML 的一些示例仍然会抛出相同的异常。
我会很感激一些见解。
谢谢, 凯瑟琳
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标签: tsql xquery-sql