我可以将 XML 直接序列化为字符串而不是使用 C# 的流吗？

Question

This example 使用StringWriter 保存序列化数据，然后调用ToString() 给出实际的string 值：

Person john = new Person();
XmlSerializer xmlSerializer = new XmlSerializer(typeof(Person));
StringWriter stringWriter = new StringWriter();
xmlSerializer.Serialize(stringWriter, john);
string serializedXML = stringWriter.ToString();

有没有更简单/更清洁的方法来做到这一点？所有Serialize() 重载似乎都使用Stream 或Writer。

更新：问了一个关于 serializing an IEnumerable via an Extension Method 的类似问题。

Answer 1

我创建了这个辅助方法，但我还没有测试它。更新了 orsogufo 的 cmets 的代码（两次）：

private string ConvertObjectToXml(object objectToSerialize)
{
    XmlSerializer xmlSerializer = new XmlSerializer(objectToSerialize.GetType());
    StringWriter stringWriter = new StringWriter();

    xmlSerializer.Serialize(stringWriter, objectToSerialize);

    return stringWriter.ToString();
}

Answer 2

扩展方法的乐趣...

var ret = john.ToXmlString()

---

public static class XmlTools
{
    public static string ToXmlString<T>(this T input)
    {
        using (var writer = new StringWriter())
        {
            input.ToXml(writer);
            return writer.ToString();
        }
    }
    public static void ToXml<T>(this T objectToSerialize, Stream stream)
    {
        new XmlSerializer(typeof(T)).Serialize(stream, objectToSerialize);
    }

    public static void ToXml<T>(this T objectToSerialize, StringWriter writer)
    {
        new XmlSerializer(typeof(T)).Serialize(writer, objectToSerialize);
    }
}

Answer 3

或多或少与您相同的解决方案，只是使用扩展方法：

static class XmlExtensions {

    // serialize an object to an XML string
    public static string ToXml(this object obj) {
        // remove the default namespaces
        XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
        ns.Add(string.Empty, string.Empty);
        // serialize to string
        XmlSerializer xs = new XmlSerializer(obj.GetType());
        StringWriter sw = new StringWriter();
        xs.Serialize(sw, obj, ns);
        return sw.GetStringBuilder().ToString();
    }

}

[XmlType("Element")]
public class Element {
    [XmlAttribute("name")]
    public string name;
}

class Program {
    static void Main(string[] args) {
        Element el = new Element();
        el.name = "test";
        Console.WriteLine(el.ToXml());
    }
}

Answer 4

似乎没有人真正回答他的问题，不，不使用流或写入器对象就无法生成 XML 字符串。