我应该使用什么 TypeScript 类型来引用我的道具中的匹配对象？

Question

在我的 React 容器/组件中，我可以使用哪种类型来引用 React Router DOM 包含的 match 部分？

interface Props {
  match: any // <= What could I use here instead of any?
}

export class ProductContainer extends React.Component<Props> {
  // ...
}

Answer 1

这是我测试的完整示例。

DemoComponent.tsx

// Created by BaiJiFeiLong@gmail.com at 2021/9/25 20:15

import React from "react";
import {RouteComponentProps} from "react-router"

export default class DemoComponent extends React.Component<{
    prop1: string,
    prop2: string,
    prop3: string
} & RouteComponentProps<{
    param1: string,
    param2: string,
    param3: string
}>, {
    state1: string,
    state2: string,
    state3: string
}> {

    static defaultProps = {
        prop1: "PROP1",
        prop2: "PROP2",
        prop3: "PROP3"
    }

    constructor(props: any) {
        super(props);
        this.state = {
            state1: "STATE1",
            state2: "STATE2",
            state3: "STATE3"
        }
    }


    render() {
        return <ul>
            <li>prop1 = {this.props.prop1}</li>
            <li>prop2 = {this.props.prop2}</li>
            <li>prop3 = {this.props.prop3}</li>
            <li>state1 = {this.state.state1}</li>
            <li>state2 = {this.state.state2}</li>
            <li>state3 = {this.state.state3}</li>
            <li>param1 = {this.props.match.params.param1}</li>
            <li>param2 = {this.props.match.params.param2}</li>
            <li>param3 = {this.props.match.params.param3}</li>
        </ul>
    }
}

路线

<Route exact path="/demo/:param1/:param2/:param3" component={DemoComponent}/>

来电

/demo/foo/bar/baz

结果

prop1 = PROP1
prop2 = PROP2
prop3 = PROP3
state1 = STATE1
state2 = STATE2
state3 = STATE3
param1 = foo
param2 = bar
param3 = baz

Answer 2

简单的解决方案

import { RouteComponentProps } from "react-router-dom";

const Container = ({ match }: RouteComponentProps<{ showId?: string}>) => {
 const { showId } = match.params?.showId;//in case you need to take params
}

Answer 3

问题是即使在为match<Params> 创建了一个接口之后，类型警告仍然存在。这是对我有用的代码：

interface MatchParams {
    firstParam: string;
    optionalParam?: string;
}

export const CreditPortfolioDetail: FC<RouteComponentProps<MatchParams>> = (props) => {
    const { firstParam, optionalParam} = props.match.params; 
    // ...
}

Answer 4

您不需要显式添加它。你可以使用来自@types/react-router 的RouteComponentProps<P> 作为道具的基本接口。 P 是匹配参数的类型。

import { RouteComponentProps } from 'react-router';

// example route
<Route path="/products/:name" component={ProductContainer} />

interface MatchParams {
    name: string;
}

interface Props extends RouteComponentProps<MatchParams> {
}

// from typings
import * as H from "history";

export interface RouteComponentProps<P> {
  match: match<P>;
  location: H.Location;
  history: H.History;
  staticContext?: any;
}

export interface match<P> {
  params: P;
  isExact: boolean;
  path: string;
  url: string;
}

Answer 5

要添加到上面@Nazar554 的答案，RouteComponentProps 类型应从react-router-dom 导入，并按如下方式实现。

import {BrowserRouter as Router, Route, RouteComponentProps } from 'react-router-dom';

interface MatchParams {
    name: string;
}

interface MatchProps extends RouteComponentProps<MatchParams> {
}

此外，为了允许可重复使用的组件，render() 函数允许您仅传递组件需要的内容，而不是整个 RouteComponentProps。

<Route path="/products/:name" render={( {match}: MatchProps) => (
    <ProductContainer name={match.params.name} /> )} />

// Now Product container takes a `string`, rather than a `MatchProps`
// This allows us to use ProductContainer elsewhere, in a non-router setting!
const ProductContainer = ( {name}: string ) => {
     return (<h1>Product Container Named: {name}</h1>)
}