使用布尔值重复 while 循环答案

【问题标题】：Repeated while loop with boolean使用布尔值重复 while 循环
【发布时间】：2021-11-09 08:08:25
【问题描述】：

对不起，如果这被认为是垃圾邮件，我遇到的另一个问题是这个 while 循环无条件运行，我不知道如何解决它。

代码：

while anotherNum == True:
    playerNum = random.randint(1,10)
    total = total + playerNum
    print("")
    print("Your number is ", str(playerNum) + ".")
    print("You have " + str(total) + " in total.")
    print("")
    again = input("Roll another number? <Y or N> ")
    print("")
    if again == "Y":
      anotherNum == True
    else:
      anotherNum == False
      break
  #game finished now
print("Computer got", pcNum)
print("You got", total)
#checking for winner
while anotherNum == False:
  if (total <= 13) and (total > pcNum): 
    print("You,", name, "have won!")
  elif (pcNum <= 13) and (pcNum > total):
    print("The computer has bested you,", name + "!")
  else:
    if (total == pcNum) and (total <= 13):
      print("Draw...")
    elif (pcNum > 13) and (total <= 13):
      print("You,", name + " have won!")
    else:
      print("Both of you have lost. Wow...")

输出：

Your number is  2.
You have 2 in total.

Roll another number? <Y or N> n


Your number is  3.
You have 3 in total.

Roll another number? <Y or N> N


Your number is  3.
You have 3 in total.

Roll another number? <Y or N> N


Your number is  9.
You have 9 in total.

while 循环不会转到#game finished now 评论区域，而是重复该过程，同时仅忽略 total = total + playerNum 命令。

【问题讨论】：

标签： python while-loop boolean

【解决方案1】：

您的代码（经过最少的修正）运行良好：

import random
total = 0
anotherNum = True

while anotherNum == True:
    playerNum = random.randint(1,10)
    total = total + playerNum
    print("")
    print("Your number is ", str(playerNum) + ".")
    print("You have " + str(total) + " in total.")
    print("")
    again = input("Roll another number? <y or n> ")
    print("")
    if again == "y":
        anotherNum = True
    else:
        anotherNum = False
        break
print("You got", total)

运行代码后得到的输出：

Your number is  7.
You have 7 in total.

Roll another number? <y or n>  y


Your number is  9.
You have 16 in total.

Roll another number? <y or n>  y


Your number is  10.
You have 26 in total.

Roll another number? <y or n>  y


Your number is  2.
You have 28 in total.

Roll another number? <y or n>  y


Your number is  6.
You have 34 in total.

Roll another number? <y or n>  n

You got 34

【讨论】：

【解决方案2】：

尝试删除break并将==更改为=

import random

total = 0
anotherNum = True

while anotherNum == True:
    playerNum = random.randint(1, 10)
    total += playerNum
    print("")
    print(f"Your number is {playerNum}.")
    print(f"You have {total} in total.")
    print("")
    again = input("Roll another number? <Y or N> ")
    print("")
    if again == "Y":
        anotherNum = True  # <- HERE
    else:
        anotherNum = False  # <- HERE

或不带anotherNum 变量：

import random

total = 0

while True:
    playerNum = random.randint(1, 10)
    total += playerNum
    print("")
    print(f"Your number is {playerNum}.")
    print(f"You have {total} in total.")
    print("")
    again = input("Roll another number? <Y or N> ")
    print("")
    if again == 'N':
        break

【讨论】：

【解决方案3】：

我会这样做。

while anotherNum:
    playerNum = random.randint(1,10)
    total += playerNum
    print("")
    print("Your number is ", str(playerNum) + ".")
    print("You have " + str(total) + " in total.")
    print("")
    again = input("Roll another number? <Y or N> ")
    print("")
    anotherNum = (again == "Y")

这样你可以避免if <blank> then true else false导致你在这里犯错（简单的==而不是=）

【讨论】：

我还是有同样的问题。
您确定输入的是 "Y" ，而不是 "y" 吗？这将导致问题...尝试再次打印以确保？请注意，第一个 = 只有一个字符，第二个是 "=="

【解决方案4】：

你没有改变价值

if again == "Y":
 anotherNum == True
 else:
 anotherNum == False
 break

你应该使用 1 个等号，因为它是一个赋值

if again == "Y":
 anotherNum = True
 else:
 anotherNum = False
 break

【讨论】：