在没有 Linq 的情况下解析和访问 XML [关闭]

Question

我正在使用一个允许 XML 但不允许 Linq 的平台，所以我必须在没有 XElement 和 XDocument 的情况下解析 XML，所以我应该使用什么来代替这两个？ 我还找到了一个代码，如果有人可以解释我如何转换它

// parse the document (this is your doc but I've made the xml parseable)
var doc = XDocument.Parse(@"<chars>
        <character name=""MyChar1"">
        <skill1 type=""attack"" damage=""30"">
            description of skill1
            <name>Skill name</name>
            <class1 type=""The Class Type""></class1>
            <class2 type=""The Class Type 2""></class2>
        </skill1>
        </character>
    <character name=""MyChar2"">
        <skill1 type=""attack"" damage=""30""></skill1>
    </character>
</chars>");

// Access a skill1 type(attribute) where the name(attribute) is "MyChar" 
// this is pretty easy with LINQ. We first get all descendant nodes of type "character"
var skillWhereNameIsMyChar1 = doc.Descendants("character")
    // then take the single one with an attribute named "value"
    .Single(ch => ch.Attribute("name") != null && ch.Attribute("name").Value == "MyChar1")
    // and take that element's child element of type skill1 
    .Element("skill1");
// this will print <skill1 ... /skill1>. However, this is an XElement object, not a string
// so you can continue to access inner text, attributes, children etc.
Console.WriteLine(skillWhereNameIsMyChar1);

// 2. Access the description of skill1 where name(att) is "MyChar1"
// this is tricky because the description text is just floating among other tags
// if description were wrapped in <description></description>, this would be simply
// var description = skillWhereNameIsMyChar1.Element("description").Value;
// here's the hacky way I found to get it in the current xml:

// first get the full value (inner text) of the skill node (includes "Skill Name")
var fullValue = skillWhereNameIsMyChar1.Value;
// then get the concatenated full values of all child nodes (= "Skill Name")
var innerValues = string.Join("", skillWhereNameIsMyChar1.Elements().Select(e => e.Value));
// get the description by dropping off the trailing characters that are actually inner values
// by limiting the length to the full length - the length of the non-description characters
var description = fullValue.Substring(0, length: fullValue.Length - innerValues.Length);
Console.WriteLine(description);

Answer 1

您需要使用 System.Xml.XmlDocument 而不是 System.Xml.Linq.XDocument。此外，您需要使用 XPath 来找到您指定的元素。如果您不熟悉 XPath，学习起来会有些复杂；相反，请查看此链接：该帖子的答案提供了一种访问 XML 属性的非常简单的方法： Read XML Attribute using XmlDocument