如何返回给定 .csv 文件的值的总和？

Question

我有一个这样的 .csv 文件，它有单词和值：

string1, 102, 90, 23
string2, 89, 45, 21
...
hi, 1, 3, 5
example, 2, 0, 2
someone, 1, 1, 1
hope, 0, 0, 0
stringN, 923, 23892, 9292
stringnN-1, 2903, 49058, 4859

还有很多这样的单词：

lis__ = [[Hi this is an example, this site is nice!.],...,[I hope someone can help]]

如何返回出现在lis__ 中的每个单词的值的总和。对于上述实例，输出将是这样的：

对于第一个子列表：

    [Hi this is an example, this site is nice!.]

In:
    hi, 1, 3, 5
    example, 2, 0, 2
    someone, 1, 1, 1
    hope, 0, 0, 0

Then add value one with value one, two with two and three with three:

Out:
[(3,3,7)]

然后对于第二个子列表，将值 1 与值 1、2 与 2、3 与 3 相加：

In:
    [I hope someone can help]
    hi, 1, 3, 5
    example, 2, 0, 2
    someone, 1, 1, 1
    hope, 0, 0, 0
out:
    [(1,1,1)]

最后：

[(3,3,7),...,(1,1,1)]

其中... 是无限的字符串或元组。可能这个任务可以用csv 模块来完成，知道如何解决这个问题吗？提前谢谢各位！

Answer 1

怎么样：

import csv
import re

class Score(object):
    def __init__(self, *args):
        self.lst = args

    def __repr__(self):
        return str(tuple(self.lst))

    def __iadd__(self, other):
        new = [self.lst[i] + other.lst[i] for i in range(3)]
        return Score(*new)


lis__ = [
    'Hi this is an example, this site is nice!.',
    'I hope someone can help',
]

# Build word_scores dictionary, keyed by word
word_scores = {}
with open('yourcsv.csv') as f:
    reader = csv.reader(f)
    for line in reader:
        word_scores[line[0].lower()] = Score(*map(int, line[1:]))


# Loop over lis__, computing the total score for each element (elem_score),
#    append it to line_scores
line_scores = []
for elem in lis__:
    elem_score = Score(0,0,0)
    for word in re.split(r'[^\w]+', elem):
        try:
            score = word_scores[word.lower()]
            print("  Found: %s %s" % (word.lower(), score))
            elem_score += score
        except KeyError:
            pass
    print("%s : %s" % (elem_score, elem))
    line_scores.append(elem_score)

print
print "Line Scores:"
print line_scores

输出：

找到：hi (1, 3, 5) 找到：示例 (2, 0, 2) (3, 3, 7) : 嗨，这是一个例子，这个网站很好！ 找到：希望 (0, 0, 0) 找到：某人 (1, 1, 1) (1, 1, 1) : 我希望有人能帮忙 线分数： [(3, 3, 7), (1, 1, 1)]