【问题标题】:Iterate over rows and columns in csv/xlsx file python 3迭代csv/xlsx文件python 3中的行和列
【发布时间】:2017-10-02 09:36:37
【问题描述】:

我是 Stack Overflow 的新手,遇到了一个我无法解决的问题。 我有一个 csv 文件或 excel(基本上是一个表格)并希望在 Python 3 中执行以下操作:

Column Header,"r269_d","r295_A","r295_R","r299_A","r325_D","r326_A"

id1,"0.0","2.29","0.0","1.3","0.0","188.4"

id2,"0.0","1.0","0.0","0.6","0.0","0.0"

对于这个 csv 文件,我想:

  1. 进入第一行 (id1)

  2. 检查第 1 列 (r269_d)

    2.1 如果 col1 = 0 的值,则将 0 写入新的 result_string

    2.2 如果 col1 的值 != 0 将 1 写入新的 result_string

  3. 检查第 2 列 (r295_A)

    3.1 如果 col2 = 0 的值,则将 0 写入与 2.1 中提到的相同的 result_string

    3.2 如果 col2 的值 != 0 将 1 写入与 2.1 中提到的相同的 result_string

  4. 对所有列都这样做

  5. 转到下一行并执行相同操作。

最后我想要这样的东西:

Column Header,"r269_d","r295_A","r295_R","r299_A","r325_D","r326_A", "result_string"

id1,"0.0","2.29","0.0","1.3","0.0","188.4","010101"

id2,"0.0","1.0","0.0","0.6","0.0","0.0","010100"

【问题讨论】:

  • 谷歌“python csv”看看你能走多远。
  • 检查 csv 的 python csv 模块。对于 xlsx,您可以使用 xlsxwriter。
  • 请查看pyexcel

标签: python excel csv pandas


【解决方案1】:

熊猫解决方案:

import pandas as pd
import numpy as np

df = pd.read_csv(r'/path/to/file.csv')

df['result_string'] = (df.filter(regex='r\d+')
                         .ne(0).astype(np.int8).astype(str)
                         .apply(''.join, axis=1))

df.to_csv(r'/path/to/result.csv', index=False)

源 CSV 文件:

col,r269_d,r295_A,r295_R,r299_A,r325_D,r326_A
id1,0.0,2.29,0.0,1.3,0.0,188.4
id2,0.0,1.0,0.0,0.6,0.0,0.0

已解析的 DF:

In [169]: df
Out[169]:
   col  r269_d  r295_A  r295_R  r299_A  r325_D  r326_A
0  id1     0.0    2.29     0.0     1.3     0.0   188.4
1  id2     0.0    1.00     0.0     0.6     0.0     0.0

结果:

In [170]: df['result_string'] = (df.filter(regex='r\d+')
     ...:                          .ne(0).astype(np.int8).astype(str)
     ...:                          .apply(''.join, axis=1))
     ...:

In [171]: df
Out[171]:
   col  r269_d  r295_A  r295_R  r299_A  r325_D  r326_A result_string
0  id1     0.0    2.29     0.0     1.3     0.0   188.4        010101
1  id2     0.0    1.00     0.0     0.6     0.0     0.0        010100

In [172]: df.to_csv(r'c:/temp/result.csv', index=False)

生成的 CSV:

col,r269_d,r295_A,r295_R,r299_A,r325_D,r326_A,result_string
id1,0.0,2.29,0.0,1.3,0.0,188.4,010101
id2,0.0,1.0,0.0,0.6,0.0,0.0,010100

【讨论】:

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