如何在php中为每个级别计算15级深度的成员

Question

我非常需要计算每个级别的每个成员我有 15 级深度佣金模型，所以我可以计算第一级但无法计算一个人在他/她的下线中拥有的整个团队。我想计算每个级别有多少成员。 比如一级 10 名成员，二级 55 名成员，三级 35 名成员等。 我需要计算第一级、第二级......直到第 15 级的父 ID 的成员总数。 我可以指望第一级像

$result = mysqli_query($con, "SELECT count(*) FROM affiliateuser where referedby = '" . $_SESSION['username'] . "' AND active = 1");

如果您需要任何澄清，请发表评论，我会解释。 我在这里分享我的第一个 2 级代码。请检查下面的代码。

开始拉取第一级下线用户

$totalref = 0;
$totalrefear = 0;
$query = "SELECT fname,email,doj,active,username,level,pcktaken FROM affiliateuser where referedby = '" . $_SESSION['username'] . "'";
$result = mysqli_query($con, $query);
while($row = mysqli_fetch_array($result)) {
    $ac = "$row[active]";
    $countusername = "$row[username]";
    $countuserlevel = "$row[level]";
    $pcktook = "$row[pcktaken]";
}

开始获取第二级下线用户

$totalrefear = 0;
$query = "SELECT fname,email,doj,active,level,username FROM affiliateuser where referedby = '" . $_SESSION['username'] . "'";
$result = mysqli_query($con, $query);
while($row = mysqli_fetch_array($result)) {
    $ac = "$row[active]";
    $countusername = "$row[username]";
    $countuserlevel = "$row[level]";
    $query2level = "SELECT fname,email,doj,active,level,username,pcktaken FROM affiliateuser where referedby = '$countusername'";
    $result2level = mysqli_query($con, $query2level);
    while($row2 = mysqli_fetch_array($result2level)) {
        $ac2 = "$row2[active]";
        $countusername2 = "$row2[username]";
        $countuserlevel2 = "$row2[level]";
        $pcktook = "$row2[pcktaken]";
    }
}

我正在尝试使用此查询来计算父级第二级的用户。但它算我整个数据库用户。我只想统计 2 级用户。请有大神帮我解决一下吗？

$queryridd =mysqli_query($con, "SELECT COUNT(Id) AS countt, level AS Lebel from affiliateuser WHERE level = '$countuserlevel' GROUP BY level");

Answer 1

假设您有一个 parent_id 字段，您可以计算有多少条记录的 parent_id 等于您正在查看的记录。要更上一层楼，您只需对刚刚获得的每条记录重复一次即可。

现在……你是怎么做到的？

首先，您的数据库需要正确规划。从simple parent - child using recursion, to materialized path, to nested sets 开始，有很多方法可以制作树状结构。每个都有优点和缺点。我个人喜欢物化路径；但是您的应用程序的树的深度使父子的一些变化更有可能。

那么数据库结构是什么样的呢？

Superheroes
----------
id         <--\
parent_id  ---/
name

如果你有这样的层次结构：

                           1 Steven Rogers 
                           /             \
                  2 Bruce Banner       3 Wally West
                  /          \
       4 Peter Parker     5 Jay Garrick
           /        \
6 Barry Allen   7 Reed Richards

你的桌子应该是这样的：

       superheroes
       -----------
id   parent_id   name
1    0           Steven Rogers
2    1           Bruce Banner
3    1           Wally West
4    2           Peter Parker
5    2           Jay Garrick
6    4           Barry Allen
7    4           Reed Richards

要查找史蒂夫·罗杰斯正下方的人，

$sth = $dbh->prepare("select id,name from superheroes where parent_id=?");
$sth->execute(array(1));
$result = $sth->fetchAll();

要查找彼得·帕克正下方的人，

$sth = $dbh->prepare("select id,name from superheroes where parent_id=?");
$sth->execute(array(4));
$result = $sth->fetchAll();

太棒了，升级了一级。我如何获得下一个级别？这是一项功能的工作。 （实际上，一个类会更好，因为范围更容易处理。）

class CountDownLine {

    public function __construct($database) {

        $this->db = $database;
    }

    public function getDownline($id, $depth=2) {

        $stack = array($id);
        for($i=1; $i<=$depth; $i++) {

            // create an array of levels, each holding an array of child ids for that level
            $stack[$i] = $this->getChildren($stack[$i-1]);
        }

        return $stack;

    }

    public function countLevel($level) {

         // expects an array of child ids
         settype($level, 'array');

         return sizeof($level);
    }

    private function getChildren($parent_ids = array()) {

        $result = array();
        $placeholders = str_repeat('?,', count($parent_ids) - 1). '?';

        $this->$db->prepare("select id from superheroes where parent_id in ($placeholders)");
        $this->$db->->execute(array($parent_ids));

        while($row=$this->$db->fetch()) {

            $results[] = $row->id;
        }

        return $results;
    }

}

它是这样工作的：

$DL = new CountDownLine(new Database); // inject your favorite database abstraction

$id = 1; // ie, id of Steve Rogers
$depth = 2;  // get the counts of his downline, only 2 deep.

$downline_array = $DL->getDownline($id, $depth=2);

// => $downline_array[1] = [2,3]
// => $downline-array[2] = [4,5]

$count_of_first_level = $DL->countLevel($downline_array[1]);
$count_of_second_level = $DL->countLevel($downline_array[2]);

注意：这是为了展示概念。我没有在数据库上测试它。您必须调整它以使用您的数据库访问方法。

Answer 2

请使用if检查关卡，然后再进入另一个关卡

<?php

$query = "SELECT fname,email,doj,active,level,username FROM affiliateuser where referedby = '" . $_SESSION['username'] . "'";
$result = mysqli_query($con, $query);
while($row = mysqli_fetch_array($result)) {
    $ac = "$row[active]";
    $countusername = "$row[username]";
    $countuserlevel = "$row[level]";
    // use if to check the level
    if($countuserlevel == 2) { // use if to check the level

        $query2level = "SELECT fname,email,doj,active,level,username,pcktaken FROM affiliateuser where referedby = '$countusername'";
        $result2level = mysqli_query($con, $query2level);
        while($row2 = mysqli_fetch_array($result2level)) {
            $ac2 = "$row2[active]";
            $countusername2 = "$row2[username]";
            $countuserlevel2 = "$row2[level]";
            $pcktook = "$row2[pcktaken]";
        }

        $queryridd = mysqli_query($con, "SELECT COUNT(Id) AS countt, level AS Lebel from affiliateuser WHERE level = '$countuserlevel' GROUP BY level");
        while($rowbb = mysqli_fetch_array($queryridd)) {
            $countingUsers2 = "$rowbb[0]";
        }

    }
} // use if to check the level
?>
<td class='text-left'><?php echo $countingUsers2; ?></td>

Answer 3

您可以轻松获取给定用户每个级别的孩子数。

<?php
/*
* $parent_id = ID of user
* $deep = amount of depth levels
*/

function countChildrenPerLevelDeep( $parent_id, $deep = 15 ) {
    $parent_id = [$parent_id];
    $level = 1;
    $arr = [];
    $i = 1;
    do {

        if ( $parent_id ) {
            $query = 'SELECT * FROM customer WHERE parent_id=' . implode( $parent_id, ',' );

            if ( $result = $mysqli->query( $query ) ) {
                /* total children on this level */
                $arr['level_' . $level] = $result->fetch_row();

                $parent_id = [];
                /* fetch associative array */
                while ( $row = $result->fetch_assoc() ) {
                    $parent_id[] = $row['id'];
                }

                /* free result set */
                $result->close();
            } else {
                $arr['level_' . $level] = 0;
                $parent_id = [];
            }
        } else {
            $arr['level_' . $level] = 0;
            $parent_id = [];
        }

        $level++;
        $i++;
    }
    while ( $i <= $deep );

    return $arr;
}
?>

结果示例

Array
(
    [level_1] => 1
    [level_2] => 2
    [level_3] => 1
    [level_4] => 0
    [level_5] => 0
    [level_6] => 0
)