【问题标题】:list the tables only if all the listed columns exists - MySQL仅当所有列出的列都存在时才列出表 - MySQL
【发布时间】:2016-10-19 06:53:17
【问题描述】:
我尝试了以下查询来列出包含列出的 4 列的表。但它不返回任何表格。
SELECT DISTINCT TABLE_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME = 'moduleid'
AND COLUMN_NAME = 'userroleid'
AND COLUMN_NAME = 'sortorder'
AND COLUMN_NAME = 'setdefault'
AND TABLE_SCHEMA='db_name'
当我在 where 条件下只使用一列时,它会返回表格。我需要知道包含所有 4 列的表。
【问题讨论】:
标签:
mysql
information-schema
【解决方案1】:
这可能不是最优雅的解决方案,但它应该可以工作。
SELECT DISTINCT c1.TABLE_NAME
FROM INFORMATION_SCHEMA.COLUMNS c1
JOIN INFORMATION_SCHEMA.COLUMNS c2 on c1.TABLE_NAME = c2.TABLE_NAME
JOIN INFORMATION_SCHEMA.COLUMNS c3 on c1.TABLE_NAME = c3.TABLE_NAME
JOIN INFORMATION_SCHEMA.COLUMNS c4 on c1.TABLE_NAME = c4.TABLE_NAME
WHERE c1.COLUMN_NAME = 'moduleid'
AND c2.COLUMN_NAME = 'userroleid'
AND c3.COLUMN_NAME = 'sortorder'
AND c4.COLUMN_NAME = 'setdefault'
AND c1.TABLE_SCHEMA='db_name'
【解决方案2】:
如果您不想为每个附加列执行 1 次 JOIN
SELECT TABLE_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME IN ('moduleid',
'userroleid',
'sortorder',
'setdefault')
AND TABLE_SCHEMA='db_name'
GROUP BY TABLE_NAME
HAVING COUNT(*) = 4