使用spring jdbc时MySQL auto_increment 10而不是1答案

【问题标题】：MySQL auto_increment 10 instead of 1 when using spring jdbc使用spring jdbc时MySQL auto_increment 10而不是1
【发布时间】：2016-03-01 02:02:14
【问题描述】：

我一直在关注本指南进行个人项目，但我遇到了这个奇怪的问题：http://www.tutorialspoint.com/spring/spring_jdbc_example.htm

当使用 spring jdbc 库插入值时，id 的值会从 1 跳转到 11 到 21... 等等。虽然，当使用简单的插入手动查询数据库时，id 会按预期工作，即：1,2 ,3 等...

这里是信息：

spring-jdbc 4.2.3 弹簧上下文 4.3.3 mysql-connector-java 5.1.37

数据库：MySQL Community Server(GPL) 5.5.45-log 托管在 Azure 上，带有 ClearDB 插件。

创建表：

CREATE TABLE runners(
   id   INT NOT NULL AUTO_INCREMENT,
   firstName VARCHAR(20) NOT NULL,
   lastName VARCHAR(20) NOT NULL,
   location VARCHAR(20) NOT NULL,
   PRIMARY KEY (ID)
);

当我查询时：SHOW VARIABLES LIKE 'auto_inc%';，我得到： auto_increment_increment 1 auto_increment_offset 1

代码如下：

Runner.java

public class Runner{
    private Integer id;
    private String firstName;
    private String lastName;
    private String location;

    public Integer getId(){
        return this.id;
    }

    public String getFirstName(){
        return this.firstName;
    }

    public String getLastName(){
        return this.lastName;
    }

    public String getLocation(){
        return this.location;
    }

    public void setId(int id){
        this.id = id;
    }

    public void setFirstName(String firstName){
        this.firstName = firstName;
    }

    public void setLastName(String lastName){
        this.lastName = lastName;
    }

    public void setLocation(String location){
        this.location = location;
    }
}

RunnerDAO.java

public interface RunnerDAO {

       public void setDataSource(DataSource ds);

       public void create(String firstName, String lastName, String location);

       public Runner getRunner(Integer id);

       public List<Runner> listRunners();

       public void delete(Integer id);

       public void update(Integer id, String firstName, String lastName, String location);
}

RunnerJDBCTEmplate.java

public class RunnerJDBCTemplate implements RunnerDAO {
   private DataSource dataSource;
   private JdbcTemplate jdbcTemplateObject;

   public void setDataSource(DataSource dataSource) {
      this.dataSource = dataSource;
      this.jdbcTemplateObject = new JdbcTemplate(dataSource);
   }

   public void create(String firstName, String lastName, String location) {
      String SQL = "insert into runners (firstName, lastName,location) values (?, ?, ?)";

      jdbcTemplateObject.update( SQL, firstName, lastName, location);
      System.out.println("Created Record FirstName = " + firstName + " LastName = " + lastName+ " Location = " + location);
      return;
   }

   public Runner getRunner(Integer id) {
      String SQL = "select * from runners where id = ?";
      Runner runner = jdbcTemplateObject.queryForObject(SQL, new Object[]{id}, new RunnerMapper());
      return runner;
   }

   public List<Runner> listRunners() {
      String SQL = "select * from runners";
      List <Runner> runners = jdbcTemplateObject.query(SQL,new RunnerMapper());
      return runners;
   }

   public void delete(Integer id){
      String SQL = "delete from runners where id = ?";
      jdbcTemplateObject.update(SQL, id);
      System.out.println("Deleted Record with ID = " + id );
      return;
   }

   public void update(Integer id, String firstName, String lastName, String location){
      String SQL = "update runners set firstName = ?,lastName = ?, location = ? where id = ?";
      jdbcTemplateObject.update(SQL, firstName, lastName, location , id);
      System.out.println("Updated Record with ID = " + id );
      return;
   }
}

RunnerMapper.java

public class RunnerMapper implements RowMapper<Runner> {
   public Runner mapRow(ResultSet rs, int rowNum) throws SQLException {
      Runner runner = new Runner();
      runner.setId(rs.getInt("id"));
      runner.setFirstName(rs.getString("firstName"));
      runner.setLastName(rs.getString("lastName"));
      runner.setLocation(rs.getString("location"));
      return runner;
   }
}

当我运行这个 main.java 时：

public static void main(String[] args) throws Exception {
        ApplicationContext context = 
                 new ClassPathXmlApplicationContext("Beans.xml");

          RunnerJDBCTemplate runnerJDBCTemplate = 
          (RunnerJDBCTemplate)context.getBean("RunnerJDBCTemplate");

          System.out.println("------Records Creation--------" );
          runnerJDBCTemplate.create("John", "Doe", "1234 street");
          runnerJDBCTemplate.create("Jane", "Dude", "5678 boulevard");
          runnerJDBCTemplate.create("Johnny", "Duh", "111 avenue");
    }
}

我在我的数据库中得到以下输出

1   John    Doe 1234 street
11  Jane    Dude    5678 boulevard
21  Johnny  Duh 111 avenue

我试过SET @@auto_increment_increment=1;

同样，手动查询时一切正常。

有人有线索吗？谢谢！

编辑

我尝试了另一个 mysql 托管，现在它运行良好。似乎 Azure ClearDb Addon 是问题的根源。不过，如果有人有解释，将不胜感激。

【问题讨论】：

标签： java mysql auto-increment spring-jdbc mysql-connector

【解决方案1】：

我相信 Azure 使用与 Heroku 相同的 ClearDB。所以这里的这个答案是最好的解释Heroku MySQL Auto Increment

简单来说就是ClearDB防止冲突的策略http://www.cleardb.com/developers/help/faq#general_16

【讨论】：

【解决方案2】：

尝试在您的代码中运行“SET @@auto_increment_increment=0”，而不是手动运行它。确保在运行任何 DML 之前运行它。

顺便说一句，您可以通过以下方式记录发送到 MySQL 的每个查询来调查根本原因：

SET GLOBAL log_output = 'TABLE';
SET GLOBAL general_log = 'ON';

-- run your java code, and wait for it to finish

SET GLOBAL general_log = 'OFF';
SELECT * FROM mysql.general_log;

这将为您提供已由您的代码（或在后台运行的任何其他代码）执行的查询。

【讨论】：