Python如果mysql行不等于输入答案

【问题标题】：Python if mysql row not equal to imputPython如果mysql行不等于输入
【发布时间】：2021-05-01 10:27:54
【问题描述】：

我将 mysql.connector 模块用于我的脚本。

这里是我的脚本，我尝试检查：我的数据库结构：名称、类型、prem、块

class database():
    def __init__(self):
        self.Database = mysql.connect(
            host='localhost',
            user='root',
            password='',
            auth_plugin='mysql_native_password'
        )
        self.cursor = self.Database.cursor()

    def GetProfileInformations(self, name):
        args = name.split(' ')
        found =  self.cursor.execute('SELECT * FROM list.raids WHERE name=' + args[0])
        sql =  self.cursor.execute('SELECT * FROM list.raids')
        rc = self.cursor.fetchall(sql)
        f = self.cursor.fetchall(found)
        # Check is imput equal to name 
        for _ in f:
            if not found:
                return
        for row in rc:
            try:
                if row[0] == args[0]:
                    if row[3] == 1:
                        if row[2] == 1:
                            print(f"Name {row[0]} found with 1")
                        else:
                            print(f"Name: {row[0]} found with 0")
                    else:
                        print(f"Name: {row[0]} found but is blocked")
            except:
                print("any error")
        self.cursor.close()

现在我的问题是为什么不使用 if exists 函数？

            if not found:
                return

祝你有美好的一天，感谢你帮助我

【问题讨论】：

标签： python python-2.7 mysql-python python-3.8

【解决方案1】：

我自己解决了：

import mysql.connector as mysql

class database():
    def __init__(self):
        self.Database = mysql.connect(
            host='localhost',
            user='root',
            password='',
            auth_plugin='mysql_native_password'
        )
        self.cursor = self.Database.cursor(buffered=True)

    def IsInSQL(self, name):
        self.cursor.execute(f'SELECT EXISTS(SELECT name AS name FROM list.raids WHERE name = "{name}")')
        f = self.cursor.fetchall()
        if not f:
            return True
        else:
            return False

    def GetProfileInformations(self, name):
        args = name.split(' ')
        self.cursor.execute('SELECT * FROM list.raids')
        rc = self.cursor.fetchall()
        if not self.IsInSQL(args[0]):
            print("nicht gefunden")
        for row in rc:
            try:
                if row[0] == args[0]:
                    if row[3] == 1:
                        if row[2] == 1:
                            print("")
                        else:
                            print("")
                    else:
                        print("not found")

            except:
                print("lel")
        self.cursor.close()

【讨论】：

【解决方案2】：

您可以使用此游标属性来检查您的查询是否有结果：

if not found.with_rows:
   print("No records found")

你也可以使用：

if found.rowcount <= 0:
    print("No records found")

【讨论】：