您可以先将a 和join 列拆分为原始DataFrame:
print (df.a.str.split(',', expand=True)
.stack()
.reset_index(level=1, drop=True)
.rename('a'))
0 1
1 1
2 2
3 1
3 2
4 2
Name: a, dtype: object
df1 = df.drop('a', axis=1)
.join(df.a.str.split(',', expand=True)
.stack()
.reset_index(level=1, drop=True)
.rename('a'))
print (df1)
b a
0 5 1
1 7 1
2 3 2
3 3 1
3 3 2
4 5 2
然后将transform 用于sum 而不加修饰。
df1['c'] = df1.groupby(['a'])['b'].transform(sum)
#cast for aggreagation join working with strings
df1['a'] = df1.a.astype(str)
print (df1)
b a c
0 5 1 15
1 7 1 15
2 3 2 11
3 3 1 15
3 3 2 11
4 5 2 11
最后groupby 按索引和聚合列按agg:
print (df1.groupby(level=0)
.agg({'a':','.join,'b':'first' ,'c':sum})
[['a','b','c']] )
a b c
0 1 5 15
1 1 7 15
2 2 3 11
3 1,2 3 26
4 2 5 11