COUNT(*) 附近的语法不正确 [关闭]答案

【问题标题】：Incorrect syntax near COUNT(*) [closed]COUNT(*) 附近的语法不正确 [关闭]
【发布时间】：2020-02-07 16:02:34
【问题描述】：

SELECT D.Drank_Naam , D.Drank_Prijs, SUM(K.Aantal) AS Aantal COUNT(*) AS StudentDeelnemer,
            + FROM Kassa K,
            + JOIN DrankVoorraad AS D ON K.Drink_ID = D.ID,
            + JOIN StudentDeelnemer AS S on K.Student_Id = S.StudentNummer, 
            + group by D.Drank_Naam, D.Drank_Prijs;

我想计算所售饮料的总和和价格，但我在 COUNT(*) 附近的语法不正确

【问题讨论】：

你忘了在COUNT(*)前加逗号
Aantal, COUNT(*) 中缺少逗号`,`
缺少逗号。

标签： mysql sql join count sum

【解决方案1】：

您的查询语句中有几个错位的逗号。这是更新的：

SELECT D.Drank_Naam , D.Drank_Prijs, SUM(K.Aantal) AS Aantal, COUNT(*) AS StudentDeelnemer
   FROM Kassa K
 JOIN DrankVoorraad AS D ON K.Drink_ID = D.ID
 JOIN StudentDeelnemer AS S on K.Student_Id = S.StudentNummer
 group by D.Drank_Naam, D.Drank_Prijs;

【讨论】：

【解决方案2】：

SELECT D.Drank_Naam , D.Drank_Prijs, SUM(K.Aantal) AS Aantal, COUNT(*) AS StudentDeelnemer,
            + FROM Kassa K,
            + JOIN DrankVoorraad AS D ON K.Drink_ID = D.ID,
            + JOIN StudentDeelnemer AS S on K.Student_Id = S.StudentNummer, 
            + group by D.Drank_Naam, D.Drank_Prijs;

【讨论】：

【解决方案3】：

你错过了一个逗号，下次再努力一点！你明白了！

【讨论】：

【解决方案4】：

这里少了一个逗号

SELECT D.Drank_Naam , D.Drank_Prijs, SUM(K.Aantal) AS Aantal, COUNT(*) AS StudentDeelnemer,
            + FROM Kassa K,
            + JOIN DrankVoorraad AS D ON K.Drink_ID = D.ID,
            + JOIN StudentDeelnemer AS S on K.Student_Id = S.StudentNummer, 
            + group by D.Drank_Naam, D.Drank_Prijs;

【讨论】：

【解决方案5】：

提问前请小心。

看看你的脚本你错过了一个逗号

SELECT D.Drank_Naam , D.Drank_Prijs, SUM(K.Aantal) AS Aantal, COUNT(*) AS StudentDeelnemer
   FROM Kassa K
 JOIN DrankVoorraad AS D ON K.Drink_ID = D.ID
 JOIN StudentDeelnemer AS S on K.Student_Id = S.StudentNummer
 group by D.Drank_Naam, D.Drank_Prijs;

【讨论】：

【解决方案6】：

当您在 SQL Server 中编写查询时，它会显示我在 SQL Server 中看到的警告行。

【讨论】：