连接列具有多个值时忽略列

Question

我有一个表 Orgs，其中包含以下数据：

ID   Name            AddressID
0    McDonalds          4
1    Starbucks          5
2    Burger King        7

我还有一个地址表，其中包含以下数据：

ID   OrgID   Address
3     0      123 Main St.
4     0      456 East Ave.
5     1      789 Young St.
6     2      5 Riverside Dr.
7     2      8 Lakeview Ave.

我需要创建一个 select 语句，从 Orgs 表中选择公司名称及其地址。 Orgs 表中的公司可以有 1 个或多个地址。如果公司只有一个地址，我不想返回该公司的任何地址。如果公司有多个地址，我想返回Orgs.AddressID = Addresses.ID的地址

所以我的结果应该是这样的：

ID   Name         Address
0    McDonalds    456 East Ave.
1    Starbucks
2    Burger King  8 Lakeview Ave.

我不知道该怎么做。感谢您的帮助！

Answer 1

SELECT 
    O.ID, O.Name, A.Address
FROM 
    Orgs O
LEFT OUTER JOIN 
    (SELECT OrgID FROM Addresses GROUP BY OrgID HAVING COUNT(*) > 1) X ON O.ID = X.OrgID
LEFT OUTER JOIN 
    Addresses A ON X.OrgID = A.OrgID AND O.AddressID = A.ID

Answer 2

没有数据本身很难，但是像这样？

SELECT 
    orgs.OrgID
,   orgs.Name
,   CASE 
        WHEN OrgCount > 1 THEN ad.Address
        ELSE '' 
    END AS Address
FROM        
(
    SELECT 
        OrgID
    ,   Name
    ,   COUNT(*) AS OrgCount
    FROM 
    Orgs
) orgs
INNER JOIN 
Addresses ad
    ON 
    ad.AddressID = orgs.AddressID 
GROUP BY 
    orgs.OrgID
,   orgs.Name
,   CASE 
        WHEN OrgCount > 1 THEN ad.Address
        ELSE '' 
    END AS Address

Answer 3

SQL fiddle with a working Demo

SELECT O.ID, O.Name, IsNull(A.addr, '') as Address
FROM Org O
LEFT JOIN 
(
  SELECT OrgID 
  FROM Address 
  GROUP BY OrgID 
  HAVING COUNT(*) > 1
) c 
  ON O.ID = c.OrgID
LEFT JOIN Address A 
  ON c.OrgID = A.OrgID 
  AND O.AddressID = A.ID