MYSQL JOIN SELECT 语句 - 省略重复项答案

【问题标题】：MYSQL JOIN SELECT Statment - omit duplicatedMYSQL JOIN SELECT 语句 - 省略重复项
【发布时间】：2011-02-16 21:05:38
【问题描述】：

我想加入以下 2 个查询，但我有重复....可以从这里删除 duplacted：

(
SELECT bar_id, bar_name, town_name, bar_telephone, 
        (subscription_type_id *2) AS subscription_type_id
FROM bar, sportactivitybar, towns, subscriptiontype
WHERE sport_activity_id_fk =14
    AND bar_id = bar_id_fk
    AND town_id = town_id_fk
    AND subscription_type_id = subscription_type_id_fk
)
UNION 
(
SELECT bar_id, bar_name, town_name, bar_telephone, 
         subscription_type_id
FROM bar, towns, subscriptiontype
WHERE town_id = town_id_fk
    AND subscription_type_id = subscription_type_id_fk
)
ORDER BY subscription_type_id DESC , RAND( )

请注意，我需要省略那些订阅类型 ID 较低的重复项

【问题讨论】：

复制什么？重复记录？重复的订阅类型 ID？
听起来您可能需要使用 INNER JOIN 而不是 UNION。

标签： mysql select join union

【解决方案1】：

如果我理解正确的话，一个简单的GROUP BY，只去掉最大订阅类型就可以了。

SELECT  dupAlias.bar_id
        , dupAlias.bar_name
        , dupAlias.town_name
        , dupAlias.bar_telephone
        , MAX(dupAlias.subscription_type_id) AS subscription_type_id
FROM    (
          SELECT  bar_id
                  , bar_name
                  , town_name
                  , bar_telephone
                  , (subscription_type_id *2) AS subscription_type_id
          FROM    bar
                  , sportactivitybar
                  , towns
                  , subscriptiontype
          WHERE   sport_activity_id_fk =14
                  AND bar_id = bar_id_fk
                  AND town_id = town_id_fk
                  AND subscription_type_id = subscription_type_id_fk
          UNION 
          SELECT  bar_id
                  , bar_name
                  , town_name
                  , bar_telephone
                  , subscription_type_id
          FROM    bar
                  , towns
                  , subscriptiontype
          WHERE   town_id = town_id_fk
                  AND subscription_type_id = subscription_type_id_fk
        ) dupAlias
GROUP BY
        dupAlias.bar_id, dupAlias.bar_name, dupAlias.town_name, dupAlias.bar_telephone
ORDER BY 
        dupAlias.subscription_type_id DESC , RAND( )

【讨论】：

感谢这工作正常！你能解释一下“dup”这个词是什么意思吗？谢谢
@mouthpiec - 它不是一个术语，它只是内部查询的别名。由于一张图片说明了一千多个单词，因此我更改了查询以反映我的意思。

【解决方案2】：

您可以将查询括起来：

SELECT bar_id, bar_name, town_name, bar_telephone, 
    max(subscription_type_id)
FROM
(
    (
    SELECT bar_id, bar_name, town_name, bar_telephone, 
            (subscription_type_id *2) AS subscription_type_id
    FROM bar, sportactivitybar, towns, subscriptiontype
    WHERE sport_activity_id_fk =14
        AND bar_id = bar_id_fk
        AND town_id = town_id_fk
        AND subscription_type_id = subscription_type_id_fk
    )
    UNION 
    (
    SELECT bar_id, bar_name, town_name, bar_telephone, 
             subscription_type_id
    FROM bar, towns, subscriptiontype
    WHERE town_id = town_id_fk
        AND subscription_type_id = subscription_type_id_fk
    )
) x
GROUP BY bar_id, bar_name, town_name, bar_telephone
ORDER BY subscription_type_id DESC , RAND( )

【讨论】：

【解决方案3】：

最快的方法是使用临时表。从那里你可以将第一个查询插入到临时表中，然后通过使用临时表的外连接或使用 not在声明中。或者您可以插入所有第二个查询，然后在临时表中的 select 中使用 group by 子句。

【讨论】：