【发布时间】:2018-08-13 08:08:56
【问题描述】:
我有一个包含大量数据的表,但表中的相关数据如下所示:
订单表:
+----------+-----------+---------------+
| OrderID | Product | Date |
+----------+-----------+---------------+
| 1 | Apple | 01/01/2001 |
| 1 | Pear | 01/01/2001 |
| 1 | Pear | 01/01/2001 |
| 1 | Orange | 01/01/2001 |
| 1 | Pineapple | 01/01/2001 |
| 2 | Cherry | 02/02/2002 |
| 2 | Cherry | 02/02/2002 |
| 3 | Orange | 03/03/2003 |
| 3 | Apple | 03/03/2003 |
| 3 | Cherry | 03/03/2003 |
+----------+-----------+---------------+
我想要一个查询来返回一个不同的订单列表,如果订单包含某些产品,则这样表示:
+----------+-----------+--------+-------+
| OrderID | Date | Apple? | Pear? |
+----------+-----------+--------+-------+
| 1 |01/01/2001 | X | X |
| 2 |02/02/2002 | | |
| 3 |03/03/2003 | X | |
+----------+-----------+--------+-------+
这里是我停下来决定寻求帮助的地方:
WITH CTEOrder AS
(
SELECT
OrderID, Product, Date,
ROW_NUMBER() OVER (PARTITION BY OrderID ORDER BY OrderID ASC) AS OrderRN
FROM
Orders
)
CTEApple as
(
SELECT
OrderID, Product, Date,
ROW_NUMBER() OVER (PARTITION BY OrderID ORDER BY OrderID ASC) AS AppleRN
FROM
Orders
WHERE
Product = 'Apple'
),
CTEPear
(
SELECT
OrderID, Product, Date,
ROW_NUMBER() OVER (PARTITION BY OrderID ORDER BY OrderID ASC) AS PearRN
FROM
Orders
WHERE
Product = 'Pear'
)
SELECT
o.OrderID, o.Product, o.Date,
co.OrderRN, a.AppleRN, p.PearRN
FROM
Orders AS o
OUTER JOIN
CTEOrder AS co ON o.OrderID = co.Orderid
OUTER JOIN
CTEApple AS a ON o.OrderID = a.OrderID
OUTER JOIN
CTEPear AS p ON o.OrderID = p.OrderID
WHERE
(co.OrderRN IS NULL AND a.AppleRN IS NULL AND p.PearRN IS NULL
OR co.OrderRN = 1 AND a.AppleRN IS NULL AND p.PearRN IS NULL
OR co.OrderRN = 1 AND a.AppleRN = 1 AND p.PearRN IS NULL
OR co.OrderRN = 1 AND a.AppleRN = 1 AND p.PearRN = 1
OR co.OrderRN = 1 AND a.AppleRN IS NULL AND p.PearRN = 1
OR co.OrderRN IS NULL AND a.AppleRN = 1 AND p.PearRN IS NULL
OR co.OrderRN IS NULL AND a.AppleRN = 1 AND p.PearRN = 1
OR co.OrderRN IS NULL AND a.AppleRN IS NULL AND p.PearRN = 1)
目前我的结果集很笨拙,有大量重复。
我认为我正朝着错误的方向前进,但我不知道 SQL Server 中有哪些其他工具可供我按照我需要的方式切割这些数据。
感谢您的指导!
这是我在 Nik Shenoy 指导下的结果集:
+----------+-----------+----------------+
| OrderID | Date | Apple? | Pear? |
+----------+-----------+----------------+
| 1 | 01/01/2001| x | NULL |
| 1 | 01/01/2001| NULL | x |
| 1 | 01/01/2001| NULL | x |
| 1 | 01/01/2001| NULL | NULL |
| 1 | 01/01/2001| NULL | NULL |
| 2 | 02/02/2002| NULL | NULL |
| 2 | 02/02/2002| NULL | NULL |
| 3 | 03/03/2003| NULL | NULL |
| 3 | 03/03/2003| x | NULL |
| 3 | 03/03/2003| NULL | NULL |
+----------+-----------+----------------+
每个订单只有 1 行的下一步是什么:
+----------+-----------+--------+-------+
| OrderID | Date | Apple? | Pear? |
+----------+-----------+--------+-------+
| 1 |01/01/2001 | X | X |
| 2 |02/02/2002 | | |
| 3 |03/03/2003 | X | |
+----------+-----------+--------+-------+
【问题讨论】:
-
我对您尝试解决看似简单的问题印象深刻。
-
该术语是“枢轴”。但是,如果您清楚简洁地说明您在值、列和列名方面所做的事情并在 Google 上搜索,您会遇到很多关键问题和答案。
标签: sql sql-server join common-table-expression outer-join