乔达时间发现小时之间的差异答案

【问题标题】：Joda time find difference between Hours乔达时间发现小时之间的差异
【发布时间】：2015-03-13 12:16:03
【问题描述】：

我有一个日期字符串：

Thu, 15 Jan 2015, 9:56 AM

我把它转换成日期变量：

Thu Jan 15 09:56:00 GMT+05:30 2015

使用：

String pattern = "EEE, d MMM yyyy, hh:mm a";
        try {
            date = new SimpleDateFormat(pattern).parse(getPref("refresh", getApplicationContext()));
        } catch (ParseException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

现在我有以下函数并将日期变量传递给下面的函数：

public static int getDiffHour(Date first) {
        int hoursBetween = Hours.hoursBetween(new LocalDate(first), new LocalDate()).getHours();
        return hoursBetween;
    }

总是返回 0。可能的原因是什么？

【问题讨论】：

请查看此链接stackoverflow.com/questions/6897027/…
stackoverflow.com/questions/3802893/…
stackoverflow.com/questions/21285161/…

标签： java android datetime jodatime

【解决方案1】：

试试这样，

int diff_hrs = getDiffHours(date,new Date());// pass your date object as startDate and pass current date as your endDate


public int getDiffHours(Date startDate, Date endDate){

  Interval interval = new Interval(startDate.getTime(), endDate.getTime());
  Period period = interval.toPeriod();
  return period.getHours();
}

【讨论】：

如果 endDate 是 currentdate 怎么办？它不允许我做一个新的 LocalDate().getTime.
您可能会因为解析日期格式不同而不是LocalDate 的JodaTime 使用的格式而面临问题。所以我会坚持让你按照我的回答中提到的那样解析它。
像魅力一样工作 :) 谢谢伙计！

【解决方案2】：

DateTimeUtils obj = new DateTimeUtils();
  SimpleDateFormat simpleDateFormat = 
            new SimpleDateFormat("EEE, d MMM yyyy, hh:mm a");

  try {

    Date date1 = simpleDateFormat.parse("Thu Jan 15 09:56:00 GMT+05:30 2015");
    Date date2 = simpleDateFormat.parse("Thu Jan 16 09:56:00 GMT+05:30 2015");

    obj.printDifference(date1, date2);

  } catch (ParseException e) {
    e.printStackTrace();
  }

}

//1 minute = 60 seconds
//1 hour = 60 x 60 = 3600
//1 day = 3600 x 24 = 86400
public void printDifference(Date startDate, Date endDate){

    //milliseconds
    long different = endDate.getTime() - startDate.getTime();

    System.out.println("startDate : " + startDate);
    System.out.println("endDate : "+ endDate);
    System.out.println("different : " + different);

    long secondsInMilli = 1000;
    long minutesInMilli = secondsInMilli * 60;
    long hoursInMilli = minutesInMilli * 60;
    long daysInMilli = hoursInMilli * 24;

    long elapsedDays = different / daysInMilli;
    different = different % daysInMilli;

    long elapsedHours = different / hoursInMilli;
    different = different % hoursInMilli;

    long elapsedMinutes = different / minutesInMilli;
    different = different % minutesInMilli;

    long elapsedSeconds = different / secondsInMilli;

    System.out.printf(
        "%d days, %d hours, %d minutes, %d seconds%n", 
        elapsedDays,
        elapsedHours, elapsedMinutes, elapsedSeconds);

}

【讨论】：

【解决方案3】：

试试下面的代码：-

public static void main(String[] args) {

    String dateStart = "01/14/2012 09:29:58";
    String dateStop = "01/15/2012 10:31:48";

    //HH converts hour in 24 hours format (0-23), day calculation
    SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");

    Date d1 = null;
    Date d2 = null;

    try {
        d1 = format.parse(dateStart);
        d2 = format.parse(dateStop);

        //in milliseconds
        long diff = d2.getTime() - d1.getTime();

        long diffSeconds = diff / 1000 % 60;
        long diffMinutes = diff / (60 * 1000) % 60;
        long diffHours = diff / (60 * 60 * 1000) % 24;
        long diffDays = diff / (24 * 60 * 60 * 1000);

        System.out.print(diffDays + " days, ");
        System.out.print(diffHours + " hours, ");
        System.out.print(diffMinutes + " minutes, ");
        System.out.print(diffSeconds + " seconds.");

    } catch (Exception e) {
        e.printStackTrace();
    }

}

欲了解更多信息，请参阅以下链接：-

http://www.mkyong.com/java/how-to-calculate-date-time-difference-in-java/

【讨论】：