需要在加入表格的标准中等同于多个属性

Question

我需要使用条件实现以下代码。

left join A a ON a.id = o.id
        and a.rules_id = b.id 
        and a.global_id = gd.id
        WHERE  m.org_name = 'PQR'

但是当我添加这样的标准时

 criteria = criteria.createAlias("a", "a", JoinType.LEFT_OUTER_JOIN,
                    Restrictions.eqProperty("a.id", "b.id")).add(Restrictions.eqProperty("a.rules_id", "b.id")).add(Restrictions.eqProperty("a.global_id", "gd.id"));

它在查询的 where 子句中如下所示：

  left join A a ON a.id = o.id
        WHERE  m.org_name = 'PQR'  and a.rules_id = b.id 
        and a.global_id = gd.id

谁能帮我写出正确的代码，怎样才能使连接条件正确？

我试过这个：

criteria = criteria.createAlias("a", "a", JoinType.LEFT_OUTER_JOIN,
                    Restrictions.eqProperty("a.id", "b.id")).add(Restrictions.eqProperty("a.rules_id", "b.id")).add(Restrictions.eqProperty("a.global_id", "gd.id"));

需要这种查询：

left join A a ON a.id = o.id
        and a.rules_id = b.id 
        and a.global_id = gd.id
        where  m.org_name = 'PQR'

Answer 1

在这种情况下，我们需要使用限制连词。

criteria = criteria.createAlias("a", "a", JoinType.LEFT_OUTER_JOIN,
                Restrictions.conjunction(
                Restrictions.eqProperty("a.id","o.id"),
                Restrictions.eqProperty("a.rules_id", "b.id")));