在准备语句时参数解包后不能使用位置参数

Question

我正在尝试将可变数量的值绑定到我准备好的语句的 IN () 条件中，并稍后在查询中绑定更多值，但出现错误：

PHP 致命错误：参数解包后无法使用位置参数。

我的代码如下：

$ccarr=explode(",", $cc);
$in = str_repeat('?,', count($ccarr) - 1) . '?';
$op_r=$tfvarr[2]; 
$budg_et=$tfvarr[1];
$budg_et1=$tfvarr111111;

$sqldesk="SELECT subsubcatid_parent, plink, deskid, sum(itprice) as totprice FROM desktop_items a, items_table b, obsubsubcat c where subsubcatid_parent IN ($in) and a.itno = b.itno and a.subsubcatid_parent=c.subsubcatid group by subsubcatid_parent, deskid having totprice > ? && totprice ? ?" ;

if($stmtdesk = $conn->prepare($sqldesk))
{
    $types = str_repeat('i', count($ccarr));
    $types .= 'isi';
    $stmtdesk->bind_param($types, ...$ccarr, $budg_et1, $op_r, $budg_et);
    $stmtdesk->execute();
    $stmtdesk->store_result();
    $stmtdesk->bind_result($subsubcatid_parentdesk, $plinkdesk, $deskiddesk, $totpricedesk);
}

如何绑定所有值而不出现解包错误？

Answer 1

我建议您将附加值推送到您的 $ccarr 数组中，这样您只需将 $ccarr 插入到 bind_param() 中。

看起来$op_r 是一个“运算符”而不是一个值。所以这不应该被束缚。 Listen to Victor。运算符值应根据硬编码值的白名单进行验证，并直接注入到您的查询字符串中。

$ccarr = explode(",", $cc);
$in = str_repeat('?,', count($ccarr) - 1) . '?';
$op_r = $tfvarr[2]; 
$budg_et = $tfvarr[1];
$budg_et1 = $tfvarr111111;

array_push($ccarr, $budg_et1, $budg_et);
$types = str_repeat('i', count($ccarr));

$sqldesk = "SELECT subsubcatid_parent, plink, deskid, SUM(itprice) AS totprice
            FROM desktop_items a
            JOIN items_table   b ON a.itno = b.itno
            JOIN obsubsubcat   c ON a.subsubcatid_parent = c.subsubcatid
            WHERE subsubcatid_parent IN ($in)
            GROUP BY subsubcatid_parent, deskid
            HAVING totprice > ? AND totprice {$op_r} ?";

$stmtdesk = $conn->prepare($sqldesk);
$stmtdesk->bind_param($types, ...$ccarr);
$stmtdesk->execute();
$stmtdesk->store_result();
$stmtdesk->bind_result($subsubcatid_parentdesk, $plinkdesk, $deskiddesk, $totpricedesk);

此外，我不建议使用 old-skool comma-JOIN。显式声明 JOIN 更清晰、更现代，并且使用 ON 表达式来描述连接关系。

最后，MySQL 中的&& 应该是AND。在你的 sql 字符串中始终使用全大写来编写 MySQL 关键字。