通过 CURL 获取变量

Question

通过 API 指导，我正在尝试获取这些参数。但是我必须编写什么 php 代码才能将结果作为变量 $result 实际得到？

CURL 安装在服务器级别。对不起，我有点迷路了。谢谢！

curl -H "Content-Type:application/json" -X POST -d '{"start_date":"2016-08-02","end_date":"2016-08-03", "columns":["paid_impressions","revenue"]}' 'http://udmserve.com/udm/radalytics_api.cpx?action=report&api_key=xxxx'

Answer 1

此代码有效。不过，您需要对其进行修改以存储您的 api 密钥

<?php

//Initiate a curl request
$ch = curl_init();

//This is your API key
$apiKey = "xxxx";

//These are your postFields
$postFields = array(
        "start_date" => "2016-08-02",
        "end_date"   => "2016-08-03",
        "columns"    => array(
                "paid_impressions",
                "revenue"
            )
    );

//Setup the curl options using variables in place of your postFields and apiKey
curl_setopt($ch, CURLOPT_URL, "http://udmserve.com/udm/radalytics_api.cpx?action=report&api_key=" . $apiKey);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode( $postFields ));
curl_setopt($ch, CURLOPT_POST, 1);

//Set up the request headers
$headers = array();
$headers[] = "Content-Type: application/json";
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);

//Make the request
$result = curl_exec($ch);

//If there was an error, display error code
if (curl_errno($ch)) {
    echo 'Error:' . curl_error($ch);
}

//Delete the curl object
curl_close ($ch);

//Show the result
echo $result;

//Or, print as array
echo '<pre>'. print_r( json_decode($result), 1 ) .'</pre>';