PHP值Mysqli stmt没有结果

Question

我的sqli 请求没有结果......就像空数据一样......我很确定我的数据库中有很多数据

这是我的代码，如果我的代码有错误，请纠正我

<?php
    // include db handler
class DB_Functions {

    private $conn;

    // constructor
    function __construct() {
        require_once 'include/DB_Connect.php';
        // connecting to database
        $db = new Db_Connect();
        $this->conn = $db->connect();
    }

        // destructor
        function __destruct() {

        }

    function getSliderList(){

        $stmt = $this->conn->prepare("SELECT cPID, image FROM sliderImage");
        $stmt->execute();
        if ($stmt->num_rows > 0 ) {
            $result = $stmt->get_result()->fetch_assoc();
            $response[] = $result;
            $stmt->close();
            echo json_encode($response);
            return true;
        } else {
            // user not found
            return false;
        }
    }
}

        $x = new DB_Functions();
        $user = $x->getSliderList();
        $response = Array();
        if($user){
                $user;
                return false;
        } else {
                $response['error'] = "Sorry an error occured. Our Problem, not you.";
                return true;
        }

?>

我的数据库连接请求

<?php
class DB_Connect {
    private $conn;

    // Connecting to database
    public function connect() {
        require_once 'include/Config.php';

        // Connecting to mysql database
        $this->conn = new mysqli(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE);

        // return database handler
        return $this->conn;
    }
}

?>

和config.php 文件

<?php

/**
 * Database config variables
 */
define("DB_HOST", "localhost");
define("DB_USER", "bxxx");
define("DB_PASSWORD", "xxxx");
define("DB_DATABASE", "xxxx");
?>

我想将结果放入数组中......并使用json_encode 发送此数据以在我的应用程序中使用它......

Answer 1

我认为您在这里不需要准备好的语句，因为您没有参数化任何数据。改用简单的查询

$stmt = $this->conn->query("SELECT cPID, image FROM sliderImage");
$response = array();
while($result = $stmt->fetch_assoc()) {
    $response[] = $result;
}
echo json_encode($response);
return true;