如何在php中用星号替换手机号码，除了最后4位数字答案

【问题标题】：How to replace the mobile number with stars except last 4 digits in php如何在php中用星号替换手机号码，除了最后4位数字
【发布时间】：2019-11-20 23:37:08
【问题描述】：

我正在尝试用除文本中最后 4 位数字之外的星号替换手机号码，并且该文本是动态的。

Eg. John's Mobile number is 8767484343 and he is from usa.
Eg. John's Mobile number is +918767484343 and he is from india.
Eg. Sunny's Mobile number is 08767484343 and he is from india.
Eg. Rahul's Mobile number is 1800-190-2312 and he is from india.



$dynamic_var = "John's Mobile number is 8767484343 and he is from usa.";

$number_extracted = preg_match_all('!\d+!', $dynamic_var , $contact_number);

// don't know what to do next

Result will be like 
Eg. John's Mobile number is ******4343 and he is from usa.
Eg. John's Mobile number is ******4343 and he is from india.
Eg. Sunny's Mobile number is ******4343 and he is from india.
Eg. Rahul's Mobile number is ******2312 and he is from india.

【问题讨论】：

将号码视为手机号码的规则是什么？即我们可以有不同类型的号码手机号码、免费电话号码、固定电话号码等。
联系电话可以是任何国家代码或没有国家代码。和免费电话号码，如 1800-120-9878，如果找到任何带 + 或 - 或没有这些数字的数字，它应该替换除最后四个之外的整个数字。
它工作正常，但将最后四位数字替换为星号。我想将除最后四位之外的所有手机号码替换为星号。
好的，试试preg_replace_callback('~\+?\d+(?:[-\s]*\d)*(?=(?:[-\s]*\d){4}(?!-?\d))~', function($m) { return preg_replace('~\d~', '*', $m[0]); }, $dynamic_var)
但它没有从其他输入中替换 + 和 -

标签： php regex replace

【解决方案1】：

根据我对您的示例输入和所需输出的了解，您不需要preg_replace_callback() 的开销。可变长度前瞻将允许您一次用星号替换一个字符，只要它后跟 4 个或更多数字或连字符即可。

代码：(Demo)

$inputs = [
    "John's Mobile number is 8767484343 and he is from usa.",
    "John's Mobile number is +918767484343 and he is from india.",
    "Sunny's Mobile number is 08767484343 and he is from Pimpri-Chinchwad, india.",
    "Rahul's Mobile number is 1800-190-2312 and he is from india."
];

var_export(preg_replace('~[+\d-](?=[\d-]{4})~', '*', $inputs));

输出：

array (
  0 => 'John\'s Mobile number is ******4343 and he is from usa.',
  1 => 'John\'s Mobile number is *********4343 and he is from india.',
  2 => 'Sunny\'s Mobile number is *******4343 and he is from Pimpri-Chinchwad, india.',
  3 => 'Rahul\'s Mobile number is *********2312 and he is from india.',
)

我可以设想一些我的 sn-p 无法处理的边缘案例，但每当您处理不符合严格格式的电话号码时，您就会陷入困境。

【讨论】：

@Rohit 从我之前的模式中删除逗号。我更新了。

【解决方案2】：

您可以像这样直接从您的 $dynamic_var 中实现这一点：

$dynamic_var = "John's Mobile number is 8767484343 and he is from usa.";
$result = preg_replace_callback('/(?<=\s)(\d|-|\+)+(?=\d{4}\s)/U', function($matches) {
    return str_repeat("*", strlen($matches[0]));
}, $dynamic_var);

【讨论】：

【解决方案3】：

旧但有用...

<?php
    echo str_repeat('*', strlen("123456789") - 4) . substr("123456789", -4);
?>

【讨论】：