【问题标题】:How go get everything from between parenthesis in PHP?如何从 PHP 中的括号之间获取所有内容?
【发布时间】:2011-04-09 17:31:09
【问题描述】:
Array(
[1] => put returns (between) paragraphs
[2] => (for) linebreak (add) 2 spaces at end
[3] => indent code by 4 (spaces!)
[4] => to make links
)
想要在括号内获取文本(对于每个值):
- 只取第一个匹配项
- 从值中删除此匹配项
- 将所有匹配项写入新数组
函数数组应该如下所示:
Array(
[1] => put returns paragraphs
[2] => linebreak (add) 2 spaces at end
[3] => indent code by 4
[4] => to make links
)
Array(
[1] => between
[2] => for
[3] => spaces!
[4] =>
)
解决办法是什么?
【问题讨论】:
标签:
php
regex
arrays
string
preg-match
【解决方案1】:
我会使用正则表达式/\((\([^()]*\)|[^()]*)\)/(这将匹配一对或两对括号)和preg_split:
$matches = array();
foreach ($arr as &$value) {
$parts = preg_split('/\((\([^()]*\)|[^()]*)\)/', $value, 2, PREG_SPLIT_DELIM_CAPTURE);
if (count($parts) > 1) {
$matches[] = current(array_splice($parts, 1, 1));
$value = implode('', $parts);
}
}
使用带有 PREG_SPLIT_DELIM_CAPTURE 标志的preg_split 将在结果数组中包含匹配的分隔符。所以找到了一个匹配,至少有三个部分。在这种情况下,第二个成员就是我们正在寻找的那个。该成员使用array_splice 删除,它也返回已删除成员的数组。为了获得被移除的成员,current 用于array_splice 的返回值。然后将其余成员重新组合在一起。
【解决方案2】:
假设您的意思是 (between) 而不是 ((between))
$arr = array(
0 => 'put returns (between) paragraphs',
1 => '(for) linebreak (add) 2 spaces at end',
2 => 'indent code by 4 (spaces!)',
3 => 'to make links');
var_dump($arr);
$new_arr = array();
foreach($arr as $key => &$str) {
if(preg_match('/(\(.*?\))/',$str,$m)) {
$new_arr[] = $m[1];
$str = preg_replace('/\(.*?\)/','',$str,1);
}
else {
$new_arr[] = '';
}
}
var_dump($arr);
var_dump($new_arr);
Working link