【发布时间】:2015-01-27 23:50:51
【问题描述】:
该脚本是关于编辑从数据库中检索到的数据。它工作正常(它编辑数据)但错误数组在脚本运行时立即显示。所以我得到了所有的错误:忘记了标题、正文、日期。
出于测试目的,例如,我省略了标题并单击提交,我只得到您忘记输入标题的信息
<?php
$page_title = 'Edit a Joke';
include ('includes/header.html');
echo '<h1>Edit a Joke</h1>';
// Check for a valid Joke ID, through GET or POST:
if ( (isset($_GET['id'])) && (is_numeric($_GET['id'])) ) { // From view_jokes.php
$id = $_GET['id'];
}
else { // No valid ID, kill the script.
echo '<p>This page has been accessed in error.</p>';
exit();
}
require ('mysqli_connect.php');
// Check if the form has been submitted:
if ($_SERVER['REQUEST_METHOD'] == 'GET') {
$errors = array();
// Check for a title
if (empty($_GET['title'])) {
$errors[] = 'You forgot to enter title.';
} else {
$tit = mysqli_real_escape_string($dbc, ($_GET['title']));
}
// Check for body:
if (empty($_GET['body'])) {
$errors[] = 'You forgot to enter body.';
} else {
$bod = mysqli_real_escape_string($dbc, ($_GET['body']));
}
// Check for date:
if (empty($_GET['date'])) {
$errors[] = 'You forgot to enter date.';
} else {
$dat = mysqli_real_escape_string($dbc, ($_GET['date']));
}
if (empty($errors)) // If everything's OK.
{
// Make the query:
$q = "UPDATE joke SET title='$tit', body='$bod', date='$dat' WHERE joke_id=$id LIMIT 1";
$r = @mysqli_query ($dbc, $q);
if (mysqli_affected_rows($dbc) == 1) { // If it ran OK.
// Print a message:
echo '<p>The joke has been edited.</p>';
} else { // If it did not run OK.
echo '<p class>The joke could not be edited. Sorry</p>'; // Public message.
}
}
else { // Report the errors.
echo '<p>The following error(s) occurred:<br />';
foreach ($errors as $msg) { // Print each error.
echo " - $msg<br />\n";
}
echo '</p><p>Please try again.</p>';
}// End of if (empty($errors)) IF.
}// End of submit conditional.
// Always show the form...
// Retrieve the joke information:
$q = "SELECT title, body, date FROM joke WHERE joke_id=$id";
$r = @mysqli_query ($dbc, $q);
if (mysqli_num_rows($r) == 1) { // Valid joke ID, show the form.
// Get the joke's information:
$row = mysqli_fetch_array ($r, MYSQLI_NUM);
// Create the form:
echo '<form action="edit_joke.php" method="GET">
<p> Title: <input type="text" name="title" value="' . $row[0] . '" /></p>
<p> Body: <input type="text" style="height: 100" size="100" name="body" value="' . $row[1] . '" /> </p>
<p> Date: <input type="date" name="date" value="' . $row[2] . '" /> </p>
<p> <input type="submit" name="submit" value="Submit" /></p>
<input type="hidden" name="id" value="' . $id . '" />
</form>';
} else { // Not a valid joke ID.
echo '<p>This page has been accessed in error.</p>';
}
mysqli_close($dbc);
?>
【问题讨论】:
-
A:使用提交按钮的命名属性将执行的代码包装在条件
isset()中。 -
我对这个问题感到困惑,因为问题没有正确形成。我可以指出代码中有很多小东西,但有些可能对您的问题没有帮助。我的第一个想法是查看
isset与isempty。 Here is a handy gist attempting to explain -
评论没有被阅读我接受。
-
@Fred-ii- 我把它弄红并试图放置 isset(submit) 但它没有用..我不想打扰你。 P.s 我是这个网站的新手。对不起
-
没关系,如果有不清楚的地方,我们会提出问题;)