如何使用 laravel 查询生成器获取 whereIn/whereBetween 的总和？

Question

我从查询中得到错误的值。谁能帮我纠正我在 laravel 项目中的查询。 mysql代码：

select SUM(amount) as total from `sales` 
where `bankid` = 1 
and `month` = 8 
and `year` = 2020
and userid in (select userid from user where bank_id=2 AND (usertype=1 OR usertype=2))

Laravel 代码：

function test($bank_id,$usertype,$month=NULL,$year=NULL){
    $query = Sales::query();
    if(is_numeric($bank_id)){
        $query->where('bankid',$bank_id);
    }
    if($month)
    $query = $query->where('month', $month);
    
    if($year)
    $query = $query->where('year', $year);

    $query = $query->select(DB::raw("SUM(amount) as total"));
    if(is_numeric($usertype)){
        $query->whereIn('userid',function ($query) use($bank_id,$usertype) {
            $query->select(DB::raw('userid'))
            ->from('user');            
            if(is_numeric($bank_id)){
                $query->where('bank_id',$bank_id);
            }                 
            if($usertype==1){
               // $query->whereBetween('usertype', [1, 2]);
                $query->where('usertype', 1);
                $query->orWhere('usertype', 2);
            } else {
                $query->where('usertype',$usertype);
            }
        });
    } 
    return $query->get()->toarray()[0]['total'];
}

当我使用查询日志并得到查询时：

DB::connection()->enableQueryLog(); 
dd($query->toSql(), $query->getBindings());

select SUM(amount) as total from `slaes` 
where `bankid` = 1 
and `month` = 8 
and `year` = 2020 
and `userid` in (select userid from `user` where `bank_id` = 1 and `usertype` =1 OR `usertype` = 2)

我需要从and userid in (select userid from user where bank_id = 1 and usertype =1 OR usertype = 2) 到and userid in (select userid from user where bank_id = 1 and (usertype =1 OR usertype = 2))

任何人都可以建议在运行此查询时尽量减少加载问题。我的数据库中有近 100 万条记录。
谢谢。

Answer 1

要将表达式放在 Laravel ORM 中的括号内，您需要在 where 中使用回调函数，如下所示：

$query->where(function($query) {
  return $query
    ->where('usertype', 1)
    ->orWhere('usertype', 2);
});

但在你的情况下，你也可以使用最短的方法：

$query->whereIn('usertype', [1,2]);