在php中使用多个对象解码json数组[重复]答案

【问题标题】：decode json array with multiple objects in php [duplicate]在php中使用多个对象解码json数组[重复]
【发布时间】：2016-03-19 16:26:55
【问题描述】：

我无法解码包含多个对象的 JSON 数组。任何形式的帮助都会被充分利用。

    {  
   "article_details":[  
      {  
         "article_code ":"000000000300028156 ",
         "diff_amnt ":"1 "
      },
      {  
         "article_code ":"000000000300028174 ",
         "diff_amnt ":"1 "
      },
      {  
         "article_code ":"000000000300028126 ",
         "diff_amnt ":"1 "
      }
   ],
   "article":[  
      {  
         "article_code ":"000000000300028156 ",
         "diff_amnt ":"1 "
      },
      {  
         "article_code ":"000000000300028174 ",
         "diff_amnt ":"1 "
      },
      {  
         "article_code ":"000000000300028126 ",
         "diff_amnt ":"1 "
      }
   ]
}

【问题讨论】：

$arr = json_decode($yourArray, true);
我已经浏览了上面的链接。但该代码无法自行运行！
答案可以在这篇文章中找到:) 资源：stackoverflow.com/a/31355640/4275093
实际上我有这些值，但我想知道我将如何分别选择文章值...！！

标签： php json

【解决方案1】：

使用json_decode() 解码 JSON 字符串，如下所示：

$json_array = json_decode($json, true);
                                  ^ When TRUE, returned objects will be converted into associative arrays.

所以你的代码应该是这样的：

// Here $json is your json string
$json_array = json_decode($json, true);

foreach($json_array as $key => $arrays){
    echo $key . "<br />";
    foreach($arrays as $array){
        foreach($array as $key => $value){
            echo $key . " => " . $value . "<br />";
        }
    }
    echo "<br />";
}

输出：

article_details
article_code => 000000000300028156
diff_amnt => 1
article_code => 000000000300028174
diff_amnt => 1
article_code => 000000000300028126
diff_amnt => 1

article
article_code => 000000000300028156
diff_amnt => 1
article_code => 000000000300028174
diff_amnt => 1
article_code => 000000000300028126
diff_amnt => 1

【讨论】：

【解决方案2】：

试试这个：

$json = '
{
   "article_details":[  
      {  
         "article_code ":"000000000300028156 ",
         "diff_amnt ":"1 "
      },
      {  
         "article_code ":"000000000300028174 ",
         "diff_amnt ":"1 "
      },
      {  
         "article_code ":"000000000300028126 ",
         "diff_amnt ":"1 "
      }
   ],
   "article":[  
      {  
         "article_code ":"000000000300028156 ",
         "diff_amnt ":"1 "
      },
      {  
         "article_code ":"000000000300028174 ",
         "diff_amnt ":"1 "
      },
      {  
         "article_code ":"000000000300028126 ",
         "diff_amnt ":"1 "
      }
   ]
}';

$key = 'article_code '; // Since your key is 'article_code ' but not 'article_code', I have to do this
$dataObject = json_decode($json);
echo $dataObject->article_details[0]->$key; // This will out put: 000000000300028156 
$dataArray = json_decode($json, true);
echo $dataArray['article_details'][0]['article_code ']; // This will out put: 000000000300028156

【讨论】：

【解决方案3】：

使用 PHP json_decode 函数

<?php
$str = '{  
   "article_details":[  
      {  
         "article_code ":"000000000300028156 ",
         "diff_amnt ":"1 "
      },
      {  
         "article_code ":"000000000300028174 ",
         "diff_amnt ":"1 "
      },
      {  
         "article_code ":"000000000300028126 ",
         "diff_amnt ":"1 "
      }
   ],
   "article":[  
      {  
         "article_code ":"000000000300028156 ",
         "diff_amnt ":"1 "
      },
      {  
         "article_code ":"000000000300028174 ",
         "diff_amnt ":"1 "
      },
      {  
         "article_code ":"000000000300028126 ",
         "diff_amnt ":"1 "
      }
   ]
}';

var_dump(json_decode($str,true));

输出：

array(2) {
  ["article_details"]=>
  array(3) {
    [0]=>
    array(2) {
      ["article_code "]=>
      string(19) "000000000300028156 "
      ["diff_amnt "]=>
      string(2) "1 "
    }
    [1]=>
    array(2) {
      ["article_code "]=>
      string(19) "000000000300028174 "
      ["diff_amnt "]=>
      string(2) "1 "
    }
    [2]=>
    array(2) {
      ["article_code "]=>
      string(19) "000000000300028126 "
      ["diff_amnt "]=>
      string(2) "1 "
    }
  }
  ["article"]=>
  array(3) {
    [0]=>
    array(2) {
      ["article_code "]=>
      string(19) "000000000300028156 "
      ["diff_amnt "]=>
      string(2) "1 "
    }
    [1]=>
    array(2) {
      ["article_code "]=>
      string(19) "000000000300028174 "
      ["diff_amnt "]=>
      string(2) "1 "
    }
    [2]=>
    array(2) {
      ["article_code "]=>
      string(19) "000000000300028126 "
      ["diff_amnt "]=>
      string(2) "1 "
    }
  }
}

【讨论】：

【解决方案4】：

json_decode 的结果是一个具有两个属性的对象，article_details 和 article
它们中的每一个都是一个对象数组。

但内部对象属性有一个尾随空格，"article_code " 和 "diff_amnt "

您可以按如下方式迭代它们

$object = json_decode($str);

foreach($object->article_details as $articleDetails){

    print $articleDetails->{"article_code "} . PHP_EOL;
}


foreach($object->article_details as $article){
    print $article->{"diff_amnt "} . PHP_EOL;
}

另请注意，这些值有一个尾随空格。
要么修复它的来源，要么像这样过滤json 字符串中的尾随空格

$jsonString = str_replace(' "','"',$jsonString);

显式删除双引号前的任何尾随空格。
然后以通常的方式访问对象属性

foreach($object->article_details as $articleDetails){
    print $articleDetails->article_code . PHP_EOL;
}


foreach($object->article_details as $article){
    print $article->diff_amnt . PHP_EOL;
}

【讨论】：