【发布时间】:2015-04-13 07:30:45
【问题描述】:
我们从 php 服务器获取 json 数据,现在我们必须在单击刷新按钮后用 json 数据填充表。数据即将到来,但它每列都未定义,并且重复了很多次,请帮我解决这个问题。
生成json数据的myphp代码
<?php
header('Access-Control-Allow-Origin: *');//Should work in Cross Domaim ajax Calling request
mysql_connect("localhost","root","2121");
mysql_select_db("service");
$query="Select * from customer where services='2'";
$result=mysql_query($query);
if ( $result === false ) {
die("Can\'t do that: " . mysql_error());
}
$retVal = array();
//MYSQL_ASSOC remove key =field identifier
while( $row = mysql_fetch_array( $result, MYSQL_ASSOC ) ) {
$retVal[] = $row;
}
echo json_encode( $retVal );
上述cod生成的json数据格式e
[
{
"cId": "65",
"address1": "PWD Road, B Narayanapura, Bengaluru, Karnataka, India",
"address2": "JSS Layout, Mysore, Karnataka, India",
"city": "Bangalore",
"comments": "ds",
"email": "you@gmail.com",
"landMark": "PWD Road, B Narayanapura, Bengaluru, Karnataka, India",
"scheduledDate": "13-Feb-2015",
"scheduledTime": "10:30 AM",
"services": "2",
"userContactNumber": "1220000000",
"userName": "Gajendra"
}
]
Java 脚本 请检查alert(data),数据库中只有一个数据,所以它应该只打印一次,但打印不止一次,我认为问题就在这里
<script>
function fetchData1(){
$(".data-contacts1-js tbody").empty();
$.get("http://localhost/service/newJobs.php", function(data)
for(var i in data){
alert(data);
var tr=$("<tr></tr>");
tr.append(
"<td>" + data[i].ID + "</td>" +
"<td>" + data[i].userName + "</td>" +
"<td>" + data[i].cust_name + "</td>" +
"<td>" + data[i].userContactNumber + "</td>" +
"<td>" + data[i].email + "</td>" +
"<td>" + data[i].address1 + "</td>" +
"<td>" + data[i].scheduledDate + "</td>" +
"<td>" + data[i].scheduledTime + "</td>");
$(".data-contacts1-js tbody").append(tr);
i++;
}
});
}
$(document).ready(function(){
$(".data-contacts1-js tbody").empty();
$('#fetchContacts1').click(function() {
fetchData1();
});
});
</script>
myhtml 表格代码
<div class="row-fluid">
<!-- block -->
<div class="block">
<div class="navbar navbar-inner block-header">
<div class="muted pull-left">Carpenter Services</div>
</div>
<div class="block-content collapse in">
<div class="span12">
<table class="data-contacts1-js table table-striped" >
<thead>
<tr>
<th>ID</th>
<th>Customer Name</th>
<th>Customer Mobile</th>
<th>Customer Email</th>
<th>Address</th>
<th>Date</th>
<th>Time</th>
<th>Status</th>
</tr>
</thead>
<tbody>
</tbody>
</table>
</div>
<button id="fetchContacts1" class="btn btn-default" type="submit">Refresh</button>
</div>
</div>
<!-- /block -->
</div>
【问题讨论】:
-
尝试正确格式化您的代码,然后我们可以进一步帮助您,或者甚至可以解决您的问题。
-
这与问题you posted earlier有何不同?
标签: javascript php json