如何在php（多维数组）中从api解码json

Question

我想在wordpress中用php解码json代码。

这是我的代码。但没有用。

function decode_func(){
    $json = file_get_contents('https://api.pray.zone/v2/times/today.json?city=jakarta');
    $decoded_json = json_decode($json,true);
    $results = $decoded_json['results'];

    foreach($results as $result) {
        $datetime = $result['datetime'];
        foreach($datetime as $datetim) {
            $times = $datetim['times'];
            foreach($times as $time) {
                echo $time['Sunrise'];
            }
        }
    }
}

add_shortcode('decode','decode_func');

Answer 1

我测试了您的代码，发现您的属性定位不正确。

要单独通过 foreach 循环而不是直接针对该属性获取 Sunrise 属性，您需要执行以下操作。

$json         = file_get_contents('https://api.pray.zone/v2/times/today.json?city=jakarta');
$decoded_json = json_decode($json,true);
$results      = $decoded_json['results'];

foreach ($results as $key => $result) {
    if ($key !== 'datetime') continue;

    foreach($result as $datetime) {
        foreach ($datetime as $time) {
            if (!empty($time['Sunrise'])) echo $time['Sunrise'];
        }
    }
}

编辑

为了同时获得城市，我用 elseif 创建了一个新的 if 条件。
代码几乎相同，因为位置不是一个多维数组，它获取城市值的次数较少

$json         = file_get_contents('https://api.pray.zone/v2/times/today.json?city=jakarta');
$decoded_json = json_decode($json,true);
$results      = $decoded_json['results'];

foreach ($results as $key => $result) {
    if ($key === 'datetime') {
        foreach($result as $datetime) {
            foreach ($datetime as $time) {
                if (!empty($time['Sunrise'])) echo $time['Sunrise'];
            }
        }
    } else if ($key === 'location') {
        if (!empty($result['city'])) echo $result['city'];
    }
}