如何在 SQL 中获取带有发票编号的唯一记录答案

【问题标题】：How to get unique record with Invoice Number in SQL如何在 SQL 中获取带有发票编号的唯一记录
【发布时间】：2020-01-22 01:12:46
【问题描述】：

我有一张这样的桌子；现在我需要带有逗号分隔的测试名称和所有列的不同发票编号。我尝试了这个查询，但我得到了一个错误。

选择列表中只能指定一个表达式，当 EXISTS 不引入子查询

SELECT DISTINCT
    PTD.InvoiceNumber, PL.PatientName, PTD.TestDate, PTD.Discount, PTD.Commission,
    (SELECT SUM(TestAmount) AS TestAmount 
     FROM tb_Patienttestdetails
     WHERE PTD.InvoiceNumber = InvoiceNumber) AS TotalAmount,  
    (TotalAmount - (PTD.Commission + PTD.Discount)) AS RealAmount,
    PTD.Remark, PL.PatientId,    
    (SELECT DISTINCT
         t1.InvoiceNumber,
         STUFF((SELECT DISTINCT '' + t2.Testname 
                FROM tb_PatientTestDetails t2  
                WHERE t1.InvoiceNumber = t2.InvoiceNumber
                FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 0, '') TestName
     FROM
         tb_PatientTestDetails t1)   
FROM 
    tb_Patienttestdetails PTD 
INNER JOIN
    tb_PatientList PL ON PTD.PatientId = PL.Id

【问题讨论】：

我正在使用 sql server 2014。我正在为此使用交叉应用。

标签： sql sql-server

【解决方案1】：

答案似乎很明显。此子查询返回两列：

(SELECT DISTINCT
     t1.InvoiceNumber,
     STUFF((SELECT DISTINCT '' + t2.Testname 
            FROM tb_PatientTestDetails t2  
            WHERE t1.InvoiceNumber = t2.InvoiceNumber
            FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 0, '') TestName
 FROM
     tb_PatientTestDetails t1)

大概，你打算这样：

SELECT PTD.InvoiceNumber, PL.PatientName, PTD.TestDate, PTD.Discount, PTD.Commission,
       SUM(PTD.TestAmount) AS TestAmount,
       SUM(PTD.TestAmount - (PTD.Commission + PTD.Discount)) AS RealAmount,
       PTD.Remark, PL.PatientId,    
       STUFF((SELECT DISTINCT '' + t2.Testname 
              FROM tb_PatientTestDetails ptd2 
              WHERE ptd.InvoiceNumber = ptd2.InvoiceNumber
              FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 0, ''
             )
            ) as tests 
FROM tb_PatientList PL JOIN
    tb_Patienttestdetails PTD 
    ON PTD.PatientId = PL.Id
GROUP BY PTD.InvoiceNumber, PL.PatientName, PTD.TestDate, PTD.Discount, PTD.Commission, PTD.Remark, PL.PatientId;

【讨论】：

【解决方案2】：

此代码解决的问题

SELECT PTD.InvoiceNumber, PL.PatientName, PTD.TestDate, PTD.Discount, PTD.Commission,
       SUM(PTD.TestAmount) AS TestAmount,
       SUM(PTD.TestAmount - (PTD.Commission + PTD.Discount)) AS RealAmount,
       PTD.Remark, PL.PatientId,   
      STUFF((SELECT distinct '' + t2.Testname from tb_PatientTestDetails t2  where PTD.InvoiceNumber = t2.InvoiceNumber FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'),1,0,'') TestName  FROM tb_PatientList PL JOIN
    tb_Patienttestdetails PTD 
    ON PTD.PatientId = PL.Id GROUP BY PTD.InvoiceNumber, PL.PatientName, PTD.TestDate, PTD.Discount, PTD.Commission, PTD.Remark, PL.PatientId;

【讨论】：